Answer:
The calculated χ² = 20.779 falls in the critical region χ² ≥ 14.46 so we accept the null hypothesis that all the means are equal and college undergraduates students do not differ from the general public with regard to their favorite sports.
Step-by-step explanation:
1) We set up our null and alternative hypothesis as
H0: the college undergraduates students do not differ from the general public with regard to their favorite sport
H0: μ1= μ2=μ3=μ4= μ5=μ6=μ7=μ
against the claim
Ha: the college undergraduates students differ from the general public with regard to their favorite sport
2) The significance level alpha is set at 0.05
3) The test statistic under H0 is ( Pearson goodness of fit test )
χ²= ∑ (O - E)²/ E where O is the observed and E is the expected frequency
which has an approximate chi square distribution with 6 (n-1) d.f
4) Computations:
Under H0 , the observed frequencies are :
Observed Expected (O-E) (O-E)² (O-E)²/E
111 (0.33*344)=
113.52 -2.52 6.3054 0.0555
39 51.6 -12.6 158.76 3.0767
46 34.4 11.6 134.56 3.911
14 20.64 -6.64 44.0896 2.136
6 17.2 -11.2 125.44 7.293
20 17.2 2.8 7.84 0.4558
<u> 108 89.44 18.56 344. 4736 3.8514 </u>
<u> 344 20.779 </u>
5) The critical region is χ² ≥ χ² (0.025)6 = 14.45
6) Conclusion:
The calculated χ² = 20.779 falls in the critical region χ² ≥ 14.46 so we reject the null hypothesis that all the means are equal and college undergraduates students do not differ from the general public with regard to their favorite sports.