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In-s [12.5K]
3 years ago
8

Could u help me with this

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Step-by-step explanation:

The vertex form of a parabola can be written as

y = a(x - h)^2 + k

where (h, k) are the coordinates of the parabola's vertex. So our parabola has the equation

y = a(x + 7)^2 + 2

Since the parabola passes through the point (-6, 4), we can solve for the constant a as follows:

4 = a(-6 + 7)^2 + 2 \Rightarrow a = 2

Therefore, the vertex form of the equation for the parabola is

y = 2(x + 7)^2 +2

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ikadub [295]

Look at the attached picture

Hope it will help you

Good luck on your assignment

Have a great day...

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3 years ago
NEED HELP ASAP WILL GIVE BRAINLIEST
Anuta_ua [19.1K]

Answer:

<em>it's either A or B hope I helped a little</em>

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2 years ago
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Determine the intercepts of the line. 7x-5=4y-67x−5=4y−67, x, minus, 5, equals, 4, y, minus, 6 xxx-intercept: \Big((left parenth
sesenic [268]

Given:

The equation of line is

7x-5=4y-6

To find:

The x and y-intercept of the given line.

Solution:

We have,

7x-5=4y-6

Putting x=0, we get

7(0)-5=4y-6

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4 0
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anygoal [31]

1 =1,1,4. 5=13,16

2 =1,4. 6=23,3

3 =18,55. 7= 25,8

4 =3,16.

ps , meanes fraction

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Which ordered pair is the solution to this system of equations?<br> y=2x-3 <br> y=7-0.5x
disa [49]

Answer:

(4, 5)

Step-by-step explanation:

y = 2x - 3

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y is already isolated on both equations, set them equal to each other:

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plug in 4 for x on either equation and solve for y:

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7 0
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