H(x) = 6x

it gives you what x is so plug that in the equation to find it.

h(2/3) = 6(2/3)
h(2/3) = 6 × 2 ÷ 3
h(2/3) = 12 ÷ 3
h(2/3) = 4

so your answer is 4.

hope this helps, God bless!

7 0

3 years ago

Anyone help please I need it

andreev551 [17]

Answer:

$-10+i\sqrt{2}$

Step-by-step explanation:

One is given the following expression:

$\sqrt{4}-\sqrt{-98}-\sqrt{144}+\sqrt{-128}$

In order to simplify and solve this problem, one must keep the following points in mind: the square root function ( $\sqrt{}$ ) is a way of requesting one to find what number times itself equals the number underneath the radical sign. One must also remember the function of taking the square root of a negative number. Remember the following property: ( $\sqrt{-1}=i$ ). Simplify the given equation. Factor each of the terms and rewrite the equation. Use the square root property to simplify the radicals and perform operations between them.

$\sqrt{4}-\sqrt{-98}-\sqrt{144}+\sqrt{-128}$

$\sqrt{2*2}-\sqrt{-1*2*7*7}-\sqrt{12*12}+\sqrt{-1*2*8*8}$

Take factors from out of under the radical:

$\sqrt{2*2}-\sqrt{-1*2*7*7}-\sqrt{12*12}+\sqrt{-1*2*8*8}$

$2-7i\sqrt{2}-12+8i\sqrt{2}$

Simplify,

$-10+i\sqrt{2}$

8 0

3 years ago