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Alinara [238K]
3 years ago
15

What sides are the triangles and the last box says can be proven or cannot

Mathematics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

side side side

Step-by-step explanation:

because three sides of each triangle is equal another triangle's

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Solve for x. Show the equation you used and your work.
IgorC [24]
Here, You need to apply "Proportionality Theorem"
According to this theorem, the ratio of components of a leg would be equal to the ratio of corresponding components of another leg.

In mathematical form, 
TV/VS = TW/WU

Substitute their values, 
14/6 = 21/(x+4)
14(x+4) = 21*6
14x+56 = 126
14x = 126-56
x = 70/14
x = 5

In short, Your Answer would be 5

Hope this helps!
4 0
3 years ago
Solve this equation please <br>5X2 - 15 = 5​
Lena [83]

Answer:

x = 2 or x = -2

Step-by-step explanation:

5x² - 15 = 5​

⇌

5x² = 15 + 5

⇌

5x² = 20

⇌

x² = 20/5 = 4

⇌

x² = 2²

⇌

x² - 2² = 0

⇌

(x - 2)(x + 2) = 0

⇌   we use the zero product property

x - 2 = 0 or x + 2 = 0

⇌

x = 2 or x = -2

4 0
3 years ago
The length of the minute hand on a clock<br> is 8 in . what is the circumference?<br><br>​
Alenkinab [10]

Answer:

16π in

Step-by-step explanation:

circumference formula is 2πr

so as the minute hand goes around with time it will travel 16π in or 50.27in

5 0
3 years ago
hello, John says the transformation rule (x, y) Right-arrow (x + 4, y + 7) can be used to describe the slide of the pre-image (4
oksian1 [2.3K]

Answer:John's error is that he applied the transformation rule to the image instead to the pre-image.The pre-image is the point you start with. To check the transformation rule, substitute the values of the coordinates (4, 5). This results to (4, 5) + (4+4, 5+7). Simplify to get (4, 5) → (8, 12). This is the image.

Step-by-step explanation:

8 0
3 years ago
What is the range of function of y-1=(x+3)^2
andreyandreev [35.5K]
The\ vertex\ form\ of\ a\ quadratic\ function:y=a(x-h)^2+k\\\\where\ (h;\ k)-the\ vertex\\---------------------------\\\\y-1=(x+3)^2\ \ \ \ |add\ 1\ to\ both\ sides\\\\y=(x+3)^2+1\\\\a=1;\ h=-3;\ k=1\\\\a=1 > 0\ therefore\ parabola\ op ens\ upward\\\\vertex\ (-3;\ 1)\\\\therefore\ the\ range\ of\ this\ function\ is\ equal\ [1;\ \infty)\\\\graph\ on\ the\ picture.

6 0
3 years ago
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