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mr_godi [17]
2 years ago
15

What is 5.202÷0.0255​

Mathematics
2 answers:
nlexa [21]2 years ago
5 0

Answer:

204

Step-by-step explanation:

prisoha [69]2 years ago
4 0

Answer:

204

Step-by-step explanation:

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A single ice skating pass costs $2.75. A monthly pass costs $24.00. Peter estimates he will go skating 8 times this month and Ju
trasher [3.6K]

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Yes they should.

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If they both buy it peter will only be spending 2 dollars more but justin will be spending $9 less

Mark Brainlies plsss

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3 years ago
HELP ME ASAP!!! On a scale used on a map, 3/4 inch represents 8 feet. On the map, what is the length of a room with an actual le
Sergio039 [100]

Answer:

D. 2 1/4

Step-by-step explanation:

3/4 inch = 8 feet

24 divided by 8 = 3

(meaning you would multiply eight three times in order to get to 24)

So....

3/4 x 3 = 2 1/4

Answer: 2 1/4

Hope this helps :)

3 0
2 years ago
Read 2 more answers
Required information Section 01.02 Exercise 14 - Effects of changing data values on mean, median, and standard deviation There a
Nutka1998 [239]

Answer:

  • Mean will Increase .
  • Median remains unchanged.
  • Standard deviation will increase.

Step-by-step explanation:

We are given that there are 14 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

Now we have to analyse the Effect of this change in data values on mean, median, and standard deviation.

  • Mean will get affected because $1,000,000 is a very huge value as compared to $100,000 and is considered to be an outlier and we know that mean is affected by outliers as mean will change to $134285.7143 after replacing $100,000 with $1,000,000 .
  • Median will not get affected as median the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .
  • Standard Deviation will also get affected as due to outlier value in the data set the numerator value will increase very much and due to which standard deviation will also increase.
5 0
3 years ago
A figure has vertices at a(3,1), b(3,6), and c(6,1). Graph the figure and classify it
BaLLatris [955]
I got 5 that’s that how that’s w
3 0
3 years ago
Please help!<br> And explain the answers too!
RideAnS [48]
1) He worked 4 hours leaving 6 more hours for him.
rate for A alone 6 baker
rate for A & B together 4
1/a+1/b=1/x
1/6+1/b=1/4
1/b=1/4-1/6
1/b=6/24-4/24
1/b=2/24
1/b=1/12
b=12
rate for wife alone 12 hours for the remaining 6 hours
check
1/6+1/12=1/4
12/72+6/72=1/4
18/72=1/4
ok
codewa
But we want to know how long it would have taken her for the whole job not just part of it
he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.

2) jessica and cynthia work in a pet shop.
it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
:
let t = time it takes them to finish (C's working time)
then
t+1 = J's working time
let 1 = completed job (all pets groomed)
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
%28%28t%2B1%29%29%2F6 + t%2F8 = 1
Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
4(t+1) + 3t = 24
4t + 4 + 3t = 24
4t + 3t = 24 - 4
7t = 20
t = 20/7
t = 26%2F7 hrs, which is: 2 + 6%2F7*60 = 2 hrs 51.43 min to finish the job

3) math club takes 40 minutes
science takes 50 minutes.
rate * time = quantity
quantity = 1 set up of the tables.
rate for math club is 1/40 of all the tables in 1 minute.
rate for science club is 1/50 of all the tables in 1 minute.
math club works for 10 minutes.
rate * time = quantity
1/40 * 10 = 10/40 = 1/4 of the tables are already set up by the math club.
there are 3/4 of the tables that still need to be set up.
rate * time = quantity
the rates of the math club and the science club are additive.
(1/40 + 1/50) * time = 3/4 of the tables that still need to be set up.
common denominator is 200.
(5/200 + 4/200) * time = 3/4.
9/200 * time = 3/4
time = 3/4 * 200/9 = 600 / 36 = 16 and 2/3 minutes.
total time required is 10 + 16 + 2/3 minutes = 26 + 2/3 minutes.
how to check.
10 minutes is used to do 1/4 of the tables.
16 + 2/3 minutes is used to do the remaining 3/4 of the tables.
combined rate of math and science club is 9/200 of the tables in 1 minute.
math club rate of 1/40 * 10 = 10/40 = 1/4 of the tables.
combine rate of 9/200 * (16 + 2/3) = 9/200 * 50/3 = 450/600 = 9/12 = 3/4 of the tables.
1/4 + 3/4 = 1 = all of the tables.

6 0
2 years ago
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