Can someone plz help me with this

garik1379 [7]

First of all, you must turn it into a decimal. To turn into a decimal, you divide by 100.

467÷100=4.67

You put aside the 4 and multiply .67 by 100

4.67= $4 \frac{67}{100}$ as a whole number.

If you want an improper fraction, multiply 100 by 4 and add 67= $\frac{467}{100}$ which is where you started from.

8 0

4 years ago

Read 2 more answers

Bob and Marie like to go to a good steakhouse. Dinners are $14 to $16 dollars with soup or salad. A beverage is $1.25. Dessert i

rosijanka [135]

Answer:

50.02

Step-by-step explanation:

7 0

3 years ago

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Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of

Naddik [55]

Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

Step-by-step explanation:

For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

50 U.S residents are sampled, so $n = 50$

4% of the U.S population has blood type AB, so $p = 0.04$ .

What is the probability that exactly 2 of the U.S. residents have blood type AB?

This is P(X = 2). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{50,2}.(0.04)^{2}.(0.96)^{48} = 0.2762$

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

5 0

3 years ago

Adding variables such as n to 10 as well as how to write that out

aliina [53]

Answer:

n + 10

Step-by-step explanation:

3 0

3 years ago

How many years will it take an account to double in value, assuming a 5.2% interest rate compounded quarterly? Round your answer

zhuklara [117]

The money account is doubled at an interest rate of 5.2 % compunded quarterly, that is, under the model of compound interest in a time period of about 3.5 years.

<h3>How to determine the doubling time of money account</h3>

The compound interest takes into account the change of money deposited in time in contrast with the simple interest, which only takes the initial amount of money into account. Please notice that four quarters equals a year.

The compound interest formula is described below:

C = C' · (1 + r/100)ⁿ (1)

Where:

r - Interest rate
n - Number of periods
C' - Initial money amount
C - Current money amount

If we know that C = 2 · C' and r = 5.2, then the doubling time is:

n = /㏒ C/C'/㏒ (1 + r/100)

n = ㏒ 2/㏒ 1.052

n ≈ 13.674

The money account is doubled at an interest rate of 5.2 % compunded quarterly, that is, under the model of compound interest in a time period of about 3.5 years. $\blacksquare$

To learn more on compound interests, we kindly invite to check this verified question: brainly.com/question/14295570

7 0

2 years ago