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Elanso [62]
3 years ago
14

2.5. Five friends went out to dinner. They each paid $13.75 for the meal, including a 7% sales tax. What was the total cost of t

he meal before the tax was added?
A.$61.75
B. $63.94
C. $64.25
D. $73.92

NO LINKS​
Mathematics
1 answer:
Liula [17]3 years ago
8 0
This is the answer D.73.92
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Can anyone please help. this is my last question!!!!
Andrej [43]

9514 1404 393

Answer:

  x = 3.6

Step-by-step explanation:

The angle bisector divides the triangle proportionally.

The base segment to the right of the bisector is 6-x, so we can write the proportion ...

  x/6 = (6-x)/4

Multiplying by 12, we get ...

  2x = 3(6 -x)

  5x = 18 . . . . . add 3x

  x = 18/5 . . . .  divide by 5

  x = 3.6

_____

<em>Alternate solution</em>

Since the base of the triangle is given as a left-part and a sum-of-both-parts, we can write the proportion the same way:

  left-part / sum-of-both-parts = x/6 = 6/(6+4)

Then the solution is x = 6(6/10) = 36/10 = 3.6.

Doing it this way avoids having x on both sides of the equation, so makes solving the equation be "one step."

8 0
3 years ago
Identify the lateral area and surface area of a regular square pyramid with base edge length 5 in. and slant height 9 in.
Galina-37 [17]
Note that a squared pyramid has a square base & 4 equal triangles.
To find the lateral the lateral area you calculate the area of the 4 equal triangles  and to find the surface area (total Area) you add the area of the base:

Area of each triangle = side (5) x slant (9) and you divide by 2

==>Aera of 1 triangle = (9x5)/2 = 45/2 & for the 4 triangles

Lateral area = (45/2) x 4 = 90 in²

Now the base area (square) = 5 x 5= 25 in²

so the surface area = 90+25 = 115 in² (answer a)
7 0
3 years ago
The expression when m=6 and n=4
OverLord2011 [107]
Step 1: plug in the numbers. 7(6)-4
Step 2 multiply 7x6 42-4
7 0
3 years ago
Find the common difference of the arithmetic<br> sequence 4, 10, 16,
DIA [1.3K]

Answer:

10it is 10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

(printers after first slot = 10; total defective printers = 2)

Then, total probability =\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}

7 0
3 years ago
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