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patriot [66]
3 years ago
15

A silent auction was held for a quilt donated for charity. Fifteen bids that were drawn randomly are listed here. What percentil

e is the bid value of $105? $85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155
Mathematics
2 answers:
lana66690 [7]3 years ago
8 0

Answer:

The answer is 27th percentile but the quiz will make you put the 20th percentile

Step-by-step explanation:

tamaranim1 [39]3 years ago
7 0

we are given

$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155

Firstly, we will arrange it in ascending order

we get

$60 $85 $95  $105  $120  $145 $155 $175 $190 $215 $235 $240 $260 $285 $315

total counts =15

place of 105 is 4

now, we can find percentile

=\frac{4}{15} *100

so, the percentile of the bid value $105 is 26.667%...........Answer

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What’s the answer for the problems 11-15 in the picture
snow_lady [41]

Answer:

11.

A) EZ Pay Plan=0.15x

B) 40 to Go Plan=0.05x+40

12.

0.15x=0.05x+40

13.

x=400 minutes

14. The solution is the amount of minutes that it takes for both plans to cost the same amount. X has one solution, so it accounts for both equations.

15. EZ Pay Plan

Step-by-step explanation:

For 11, what you need to know is that the slope (coefficient of x) is the price per minute. 0.15 per minute and 0.05 per minute are charged, and therefore are the slope for those equations. The 40 on B is because it is the y intercept. No matter how long you use the object, you will always pay at least 40 dollars.

For 12, you have to find x for the minutes used.

For 13, if you do the process algebraically,

0.15x=0.05x+40  

0.10x=40     (subtracted 0.05x from both sides)

x=400       (divided 0.10x and 40 by 0.10)

For 14, (no explanation)

For 15, if you substitute 200 as x, you would see that the EZ Pay Plan would make you pay 30 dollars while the 40 To Go Plan would make you pay 10+40 dollars, which 30<50.

(sorry for late response)

7 0
3 years ago
In the 2009-2010 school year in country A, there were 92,000 foreign students from country B. This number I 23% more than the nu
max2010maxim [7]

Answer:

\approx74796

Step-by-step explanation:

GIVEN: In the 2009-10 school year in country A, there were 92,000 foreign students from country B. This number is 23\% more than the number of students from country C.

TO FIND: How many foreign students were from country C.

SOLUTION:

Total foreign students from country B =92000

let the foreign students from country C be x

As the students from country B is 23\% more than the country C

Students from country B

92000=\frac{123}{100}x

x=\frac{9200000}{123}

x\approx74796

Hence the number of students from country C are 74796

8 0
3 years ago
Isle Royale, an island in Lake Superior, has provided an important study site of wolves and their prey. Of special interest is t
STatiana [176]

Answer:

<em>Part a) Probability that a moose in that age group is killed by a wolf</em>

  • P  (0.5 year) = 0.361
  • P (1 - 5) = 0.159
  • P (6 - 10) = 0.267
  • P (11 - 15) = 0.203
  • P (16 - 20) = 0.010

<em>Part b)</em>

  • <em>Expected age of a moose killed by a wold</em>

         μ = 5.61 years

  • <em>Stantard deviation of the ages</em>

       σ = 4.97 years

Explanation:

1) Start by arranging the table to interpret the information:

<u>Age of Moose in years          Number killed by woolves</u>

Calf (0.5)                                                 107

1 - 5                                                           47

6 - 10                                                         79

11 - 15                                                        60

16 - 20                                                        3

You can  now verify the total number of moose deaths identified as wolf kills: 107 + 47 + 79 + 60 + 3 = 296, such as stated in the first part of the question.

2) <u>First question: </u>a) For each age, group, compute the probability that a moos in that age group is killed by a wolf.

i) Formula:

Probability = number of positive outcomes / total number of events.

ii) Probability that a moose in an age group is killed by a wolf = number of moose killed by a wolf in that age group / total number of moose deaths identified as wolf kills.

iii) P  (0.5 year) = 107 / 296 = 0.361

iv) P (1 - 5) = 47 / 296 = 0.159

v) P (6 - 10) = 79 / 296 = 0.267

vi) P (11 - 15) = 60 / 296 = 0.203

vii) P (16 - 20) = 3 / 296 = 0.010

3) <u>Second question:</u> b) Consider all ages in a class equal to the class midpoint. Find the expected age of a moose killed by a wolf and the standard deviation of the ages.

i) Class       midpoint

   0.5               0.5

   1 - 5           (1 + 5) / 2 = 3

   6 - 10         (6 + 10) / 2 = 8

   11 - 15         (11 + 15) / 2 = 13

   16 - 20       (16 + 20) = 18

ii) Expected age of a moose killed by a wolf = mean of the distribution = μ

μ = Sum of the products of each probability times its age (mid point)

μ = 0.5 ( 0.361) + 3 ( 0.159) + 8 ( 0.267) + 13 ( 0.203) + 18 ( 0.010) = 5.61 years

μ = 5.61 years ← answer

iii) Stantard deviation of the ages = σ

σ = square root of the variace

variance = s = sum of the products of the squares of the differences between the mean and the class midpoint time the probability.

s =  (0.5 - 5.61)² (0.361) + (3 - 5.61)² ( 0.159) + (8  - 5.61)² ( 0.267) + (13 - 5.61)² ( 0.203) + (18 - 5.61)² ( 0.010) = 24.65

σ = √ (24.65) = 4.97 years ← answer

7 0
2 years ago
I need help finding x
Nastasia [14]
All sides of a triangle add up to 180 degrees. Since we know one angle is 93 degrees, we know that the top part is going to equal 180 degrees. We know that two of those measurements are 93 and 45, so we add those together to get 138. We subtract this from 180 to find the missing angle, which is 42 degrees. So, the left side of the triangle is equivalent to 45 degrees and the right side (x) is 42 degrees. 93 + 45 + 42 = 180. If it was asking for the measurements of the supplementary angles to the bottom angles of the triangle, then those would be (for 45) 135 and (for 42) 138, that way both angles and their supplements add up to 180 each. I hope this helps and that it’s right
8 0
3 years ago
Need to find the slope pls helppp
belka [17]

Answer:

-5/4

Step-by-step explanation:

4 0
3 years ago
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