All categories

3 years ago

Cual es el valor de la expression7×3²+3×7+6

Mathematics

1 answer:

Julli [10]3 years ago

3 0

Answer:

Step-by-step explanation:

7 x (3x3) + (3x7) +6

(7 x 9) + 21+6

63 + 21 + 6

You might be interested in

How do you use proofs to show that triangles are congruent

seropon [69]

Side Angle Side
Angle Side Angle
Side Side Side

8 0

3 years ago

Solving 2 and 3 steps equations

mojhsa [17]

Answer:

I need more detail............,.....

7 0

2 years ago

Write the equation of a line that is parallel to 3x+2y=10 and passes through the point (4,-5). Answer in slope-intercept form.

SCORPION-xisa [38]

The equation of line is:

$y = \frac{-3}{2}x+1$

Further explanation:

The standard form of equation in point-slope form is:

$y = mx+b$

Given equation is:

3x+2y=10

We have to convert it into point slope form, for which we have to isolate y on one side of equation

$3x+2y = 10\\2y = -3x +10\\y = \frac{-3}{2}x + \frac{10}{2}\\y = \frac{-3}{2}x + 5$

Comparing with standard form:

m = -3/2

As the new line is parallel to given line, their slopes will be equal

So,

$y = \frac{-3}{2}x+b$

To find the value of b, putting the given point (4,-5) in equation

$-5 = \frac{-3}{2}(4)+b\\-5 = -6+b\\b = -5+6 \\b = 1\\So\ the\ equation\ is:\\y = \frac{-3}{2}x+1$

Keywords: Point-slope form, equation of line

Learn more about point-slope form of equation at:

#LearnwithBrainly

4 0

3 years ago

Prove that if x is an positive real number such that x + x^-1 is an integer, then x^3 + x^-3 is an integer as well.

Shkiper50 [21]

Answer:

By closure property of multiplication and addition of integers,

If $x + \dfrac{1}{x}$ is an integer

∴ $\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$ is an integer

From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

$x + \dfrac{1}{x}$

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}$

By simplification of the cube of the given integer expressions, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$

Therefore, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}$

By rearranging, we get;

$x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )$

Given that $x + \dfrac{1}{x}$ is an integer, from the closure property, the product of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3$ is an integer and $3\cdot \left (x + \dfrac{1}{x} \right )$ is also an integer

Similarly the sum of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

$\therefore x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= \left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer.

4 0

3 years ago

Can somebody please help me

Levart [38]

Answer:

462 sq in

Step-by-step explanation:

3((14 2/3)(10.5))

3(154)

462

7 0

3 years ago

Cual es el valor de la expression7×3²+3×7+6​

Cual es el valor de la expression7×3²+3×7+6