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2 years ago

Determine the intercepts of the line. Do not round your answers. y=-2x-21y=−2x−21

Mathematics

2 answers:

Neko [114]2 years ago

4 0

Answer:

x(-10.5,0)

y.(0,-21)

Step-by-step explanation:

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Vladimir79 [104]2 years ago

3 0

Answer:

• For y-intercept [ x = 0 ]

${ \rm{y = - 2x - 21}} \\ \\ { \rm{y = ( - 2 \times 0) - 21}} \\ \\ { \rm{y = - 21}} \\ \\ { \boxed{ \rm{ \: y - intercept : \: (0, \: - 21) \: }}}$

• For x-intercept [ y = 0 ]

${ \rm{y = - 2x - 21}} \\ \\ { \rm{0 = - 2x - 21}} \\ \\ { \rm{2x = - 21}} \\ \\ { \rm{x = - 10.5}} \\ \\ { \boxed{ \rm{x -intercept : \: ( - 10.5, \: 0) \: }}}$

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Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

Classify the polygon as regular or irregular, and concave or convex.

Svetradugi [14.3K]

Answer:

This would be a regular polygon.

Step-by-step explanation:

A regular polygon has congruent sides and interior angles.

An irregular polygon does not have congruent sides and all interior angles.

A convex polygon does not have a interior angle greater than 180°.

Lastly, a concave polygon has only one interior angle greater than 180°.

Using the process of elimination, it would not be a convex or concave polygon. Now we have either a regular or irregular polygon. This polygon can not be a irregular polygon because all the sides are congruent. This means that this polygon is a regular polygon!

7 0

3 years ago

L1 : y = 2x , (2) find the equation of the line L2 perpendicular to L1 passing through the point P = (1, 2).

just olya [345]

Answer:

Step-by-step explanation:

Given the line L1 as y = 2x perpendicular to an unknown line L2 passing through the point P = (1, 2), we are to find the equation of line L2. to find the equation of the line L2, we will use the point-slope equation of a line expressed as y-y₀ = m(x-x₀)

m is the slope of the unknown line

(x₀, y₀) is the given point.

First is to get the slope of the known line:

comparing the line L1: y = 2x with the standard equation of the line y = mx+c, it can be seen that m = 2

Then we will calculate the slope of the required line.

Since L1 is perpendicular to L2, the product of their slope will be -1 i.e

mm₁ = -1 where m₁ is the slope of the required line L2.

Given m =2

m₁ = -1/m

m₁ = -1/2

Finally we will calculate the equation of line L2 by substituting the slope of line L2 and the point in the point slope equation above;

y-y₀ = m(x-x₀)

Given (x₀, y₀) = (1,2) and m₁ = -1/2

y-2 = -1/2(x-1)

open the parenthesis

y-2 = -x/2+1/2

multiply through by 2:

2y-4 = -x+1

2y+x = 1+4

2y+x = 5

<em>Hence the equation of the line L2 is 2y+x = 5</em>

8 0

2 years ago

What is 181.5% of 18?

inysia [295]

Answer:

32.67

Step-by-step explanation:

18% of 181.5 is 32.67, which is much easier to solve than 181.5% of 18. It works flipped over.

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3 years ago

If sin x = 0.9, what is the value of cos x?<br><br> Round the value to the nearest thousandth.

Svetlanka [38]

Sinx=0.9

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cos(arcsin0.9)=0.436

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3 years ago