F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Option D: Two irrational solutions
Explanation:
The equation is 
Subtracting 6x from both sides, we have,

Solving the equation using quadratic formula,

Simplifying the expression, we get,

Taking out the common terms and simplifying, we have,

Dividing by 3, we get,

Hence, the equation has two irrational solutions.
Answer:
(x-1)(x+7)
Step-by-step explanation:
x = 1
x = -7
These are the roots found using the quadratic formula.
Answer:
2 – 3х + 5х = 16 — 8х + 8x
2 - 8x = 16
8x = 14,
x = 1.75