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2 years ago

Please help me :) i would appreciate it

Mathematics

2 answers:

alex41 [277]2 years ago

5 0

Answer:15

Step-by-step explanation:

1. 32 + 2 (-4) - 9

2. 32 + (-8) - 9

3. 32 + (-17)

4. 15

chubhunter [2.5K]2 years ago

4 0

Answer:

D. 15

Step-by-step explanation:

Given the expression, 32 + 2n - 9, and a value of <em>n </em>= -4:

You can substitute the value of <em>n</em> into the given expression:

= 32 + 2n - 9

= 32 + 2(-4) - 9

= 32 - 8 - 9

= 15

Therefore, the correct answer is D. 15

Please mark my answers as the Brainliest if my explanations were helpful :)

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Answer:

The population of interest for this student is the students whom are enrolled in statistics classes.

Step-by-step explanation:

Sampling

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For example:

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3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205

Crank

Answer:

$P(205-0.3=204.7$

$z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$

$z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$

So we can find this probability:

$P(-1.778$

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

$P = 1-0.9243 = 0.0757$

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where $\mu=205$ and $\sigma=1.5$

We can begin finding this probability this probability

$P(205-0.3=204.7$

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And we can find the z scores for each limit and we got:

$z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$

$z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$

So we can find this probability:

$P(-1.778$

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

$P = 1-0.9243 = 0.0757$

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3 years ago

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