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Alona [7]
2 years ago
10

Simplify (a+b) ²-2ab​

Mathematics
1 answer:
Scrat [10]2 years ago
6 0

Answer:

a² + b²

Step-by-step explanation:

(a + b)² - 2ab ← expand parenthesis using FOIL

= a² + 2ab + b² - 2ab ← collect like terms

= a² + b²

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A number is 2 hundreds more than 355, what is the number?
tatiyna
I think it is 555??
355+200=555

7 0
3 years ago
According to the histogram above, how many people weigh between 150 and
Inga [223]

Answer: C. 14

3 people weigh between 150-159

4 people wiegh between 160-169

7 people wiegh between 170-179

5 0
3 years ago
Show the factors of 5 x y square + 7 x square y by tree diagram​
zlopas [31]

Answer:

Answer:

Domain = {x /x ≥ -7}

Step-by-step explanation:

The given function y =

Inside the square, negative will not come.

First let's find the domain. x + 7 must be greater than or equal to 0.

x + 7 ≥ 0

Solving x, we get

x ≥ -7

Domain = {x /x ≥ -7}

Hope this will help you.

3 0
3 years ago
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
How do I solve ?? It’s cylinders
UkoKoshka [18]
V= 3.14r^2h
10/2= r
5^2= 25
(3.14)(25)(6)
V=471
3 0
3 years ago
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