All categories

2 years ago

Simplify (a+b) ²-2ab

Mathematics

1 answer:

Scrat [10]2 years ago

6 0

Answer:

a² + b²

Step-by-step explanation:

(a + b)² - 2ab ← expand parenthesis using FOIL

= a² + 2ab + b² - 2ab ← collect like terms

= a² + b²

You might be interested in

A number is 2 hundreds more than 355, what is the number?

tatiyna

I think it is 555??
355+200=555

7 0

3 years ago

According to the histogram above, how many people weigh between 150 and

Inga [223]

Answer: C. 14

3 people weigh between 150-159

4 people wiegh between 160-169

7 people wiegh between 170-179

5 0

3 years ago

Show the factors of 5 x y square + 7 x square y by tree diagram

zlopas [31]

Answer:

Answer:

Domain = {x /x ≥ -7}

Step-by-step explanation:

The given function y =

Inside the square, negative will not come.

First let's find the domain. x + 7 must be greater than or equal to 0.

x + 7 ≥ 0

Solving x, we get

x ≥ -7

Domain = {x /x ≥ -7}

Hope this will help you.

3 0

3 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago

How do I solve ?? It’s cylinders

UkoKoshka [18]

V= 3.14r^2h
10/2= r
5^2= 25
(3.14)(25)(6)
V=471

3 0

3 years ago

Simplify (a+b) ²-2ab​

Simplify (a+b) ²-2ab