All categories

3 years ago

What two integers are 998 square root is between

Mathematics

2 answers:

nirvana33 [79]3 years ago

5 0

Answer:

q 2

Step-by-step explanation:

The square root of 998 in mathematical form is written with the radical sign like this √998. We call this the square root of 998 in radical form. The square root of 998 is a quantity (q) that when multiplied by itself will equal 998.

√998 = q × q = q 2

ExtremeBDS [4]3 years ago

5 0

Answer:

Step-by-step explanation:

Hope this helps:)

You might be interested in

The girls tennis team was interested in raising funds for an upcoming trip. The team sold tumblers for $10 and sun hats for $5

gtnhenbr [62]

The equations that can be used are 10T + 5S = 190 and T + S = 30.

<h3><u>Equations</u></h3>

Given that the girls tennis team was interested in raising funds for an upcoming trip, and the team sold tumblers for $10 and sun hats for $5, and when the sales were over, the team had earned $190 and sold 30 total products, which included a mix of tumblers and hats, to determine which equations can be used to represent the situation, the following calculations must be made:

T + S =190
-It cannot be used because it has any relationship with the price of the products.

10T + 5S = 30
-It cannot be used because it only considers the quantity variable.

T + S = 30
-It can be used as it shows the amount of products sold.

10T + 5S = 190
-It can be used because it relates the total price to the quantity of each product.

T + S = 15
-It cannot be used because it only considers the price variable.

5T + 10S = 190
-It cannot be used because it erroneously relates the price of each product.

Therefore, the equations that can be used are 10T + 5S = 190 and T + S = 30.

Learn more about equations at brainly.com/question/26511270.

5 0

3 years ago

Read 2 more answers

Help show work please

olya-2409 [2.1K]

Answer:

8x squared

Step-by-step explanation:

all you do is multiply the 4 and 2 to get the 8 and the x's multiply together causing it to square it making it 8x squared

5 0

3 years ago

If f(x) = x^1.5 - x and , g(x) = 2x^3 -x^1.5-x, find f(x)-g(x)

Brut [27]

Answer:

(f - g)(x) = -2x^3

Step-by-step explanation:

f(x) = x^1.5 - x

-g(x) = -2x^3 - x^1.5 + x

----------------------------------

(f - g)(x) = -2x^3 (answer)

8 0

3 years ago

The equation 6x2 - 132 +5 -0 has solutions of the form

MArishka [77]

Answer:

(A)

$N = -b = -(-13) = 13\\\\$

$D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49$

$M = 2a = 2(6) = 12$

(B)

$x = (\frac{5}{3} , \: \frac{1}{2})$

Step-by-step explanation:

The given equation is

$6x^2 - 13x + 5 = 0$

The solution is of the form as given by

$x=\frac{N\pm\sqrt{D}}{M}$

(A) Use the quadratic formula to solve this equation and find the appropriate integer values of N, M and D. Do not worry about simplifying the VD yet in this part of the problem.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

The equations of N, M and D are

$N = -b$

$D =b^2 -4ac$

$M = 2a$

The values of a, b and c are

$a = 6 \\\\b = -13 \\\\c = 5$

So,

$N = -b = -(-13) = 13\\\\$

$D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49$

$M = 2a = 2(6) = 12$

(B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: -5/2-3/4

N = 13

D = 49

M = 12

$x=\frac{13\pm\sqrt{49}}{12}$

$x=\frac{13\pm7}{12}$

$x=\frac{13+7}{12}$ and $x=\frac{13-7}{12}$

$x=\frac{20}{12}$ and $x=\frac{6}{12}$

$x=\frac{5}{3}$ and $x=\frac{1}{2}$

$x = (\frac{5}{3} , \: \frac{1}{2})$

5 0

3 years ago

ALL YOU NEED TO DO IS DRAW THIS!!!!! Circle ω1 with center K of radius 4 and circle ω2 of radius 6 intersect at points W and U.

maria [59]

Answer:

WU = (14√13)/13 ≈ 6.6564

Step-by-step explanation:

Call the incenter of ∆KWU point A. Call the center of circle ω2 point B.

Then ∠KWA has half the measure of arc WA. ∠AWU is congruent to ∠KWA, so also has half the arc measure. That is, ∠KWU has the same measure as arc WA and ∠KBW.

KB is a perpendicular bisector of chord WU, so ∆KWB is a right triangle, of which WU is twice the altitude to base KB.

The length of KB can be found several ways. One of them is to use the Pythagorean theorem:

KB² = KW² +WB² = 4² +6² = 52

KB = √52 = 2√13

The area of triangle KWB is ...

area ∆KWB = (1/2)KW·WB = (1/2)(4)(6) = 12 . . . . square units

Using KB as the base in the area calculation, we have ...

area ∆KWB = (1/2)(KB)(WU/2)

12 = KB·WU/4

WU = 48/KB = 48/(2√13) = 24/√13

WU = (24√13)/13 ≈ 6.6564

7 0

3 years ago