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Colt1911 [192]
4 years ago
11

Alejandro places a gift in a rectangular box with a length of 7.5 inches, a width of 4.5 inches, and a height of 3.25 inches. Wh

at is the amount of wrapping paper Alejandro needs to cover the rectangular box?
Mathematics
1 answer:
AURORKA [14]4 years ago
5 0
First, you need to multiply each of these numbers. This is a rectangle so you would do l*w, l*h, and h*w. You would do all of these things and then multiply each expression by 2 to complete the equation. Then add all of them together and you have your answer. The reason you multiply by two is because there are 2 versions of this for each equation. The top and bottom, the two vertical sides, and the two horizontal sides. 7.5*4.5*2=67.5, 7.5*3.25*2=48.75, and 4.5*3.25=29.25. Now add. 67.5+48.75+29.25=145.5 as our grand total.

The answer is 145.5in^2

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In the past month, Josh rented one video game and six DVDs. The rental price for the video game who is $2.50. The rental price f
dolphi86 [110]

Answer:

total amount paid = $ 22.9

Step-by-step explanation:

total price = $ 2.5 + $3.4(6)= $22.9

5 0
3 years ago
Read 2 more answers
Solve the inequality –1 > –2(x – 4) – 5(4x – 7).
Ksivusya [100]

Answer:

x > 2

Step-by-step explanation:

–1 > –2(x – 4) – 5(4x – 7)

–1 > –2x  + 8 –20x + 35

–1 >  - 22x + 43

- 1 - 43 >  - 22x

- 44 >  - 22x

\frac{ - 44}{ - 22}   <   \frac{ - 22x}{ - 22}

2 < x

x > 2

5 0
3 years ago
Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
andrew11 [14]

Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

4 0
4 years ago
The expression 100 + 20m, gives the volume of water in Eduardo’s pool (in liters) after Eduardo spends m minutes filling his poo
Alex17521 [72]

205 liters in 5 1/4 minutes

m = 5 1/4

20 (5 1/4) = 105

100+105= 205

3 0
3 years ago
What is the product 5x and x^2+1
djyliett [7]

89 8989898989898989898

8 0
3 years ago
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