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Lady bird [3.3K]
3 years ago
12

What does the digital living network alliance standardize

Computers and Technology
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

the convergence of devices.

Explanation:

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The answer is B.

If you press the tab key when you're in the last cell of a table, you will add a new blank row
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During prereading, it is not important to pay attention to visual aids. please select the best answer from the choices provided
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True Because the visual aids will provide better hand to eye coordination
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The computer that can be used for performing the daily life tasks that might include emailing, browsing, media sharing, entertai
ad-work [718]

Answer:

Yes, this statement is completely true

Explanation:

Yes, this statement is completely true. A personal computer is a multimedia machine and can be used to complete an incredibly large number of tasks with ease. Such tasks include all of the ones listed in the question. Aside from that other tasks depend more on the skill level and understanding of the user. For example, an individual who has a vast understanding of technology and programming can create software to perform absolutely any task they may want or need to do.

5 0
3 years ago
Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
3 years ago
Question # 4
arlik [135]

Answer:

Explanatio Morse code

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