Answer:
The Laplace transform of f(t) = 1 is given by
F(s) = (1/s) for all s>0
Step-by-step explanation:
Laplace transform of a function f(t) is given as
F(s) = ∫∞₀ f(t) e⁻ˢᵗ dt
Find the Laplace transform for when f(t) = 1
F(s) = ∫∞₀ 1.e⁻ˢᵗ dt
F(s) = ∫∞₀ e⁻ˢᵗ dt = (1/s) [-e⁻ˢᵗ]∞₀
= -(1/s) [1/eˢᵗ]∞₀
Note that e^(∞) = ∞
F(s) = -(1/s) [(1/∞) - (1/e⁰)]
Note that (1/∞) = 0
F(s) = -(1/s) [0 - 1] = -(1/s) (-1) = (1/s)
Hope this Helps!!!
Answer:
x2 +2x−xy when x = 250 and y = −120 ... sic Algebra: Patterns and Equations (13:18)
Step-by-step explanation:
Answer:
the answer is 022,500
Step-by-step explanation:
hope this helps
Answer:
Your answer is in the screenshot! :)
Step-by-step explanation:
1. Solve for yy in y+7x=50y+7x=50. y=50-7x
y=50−7x
2. Substitute y=50-7xy=50−7x into 14x-5y=-2814x−5y=−28. 49x-250=-28
49x−250=−28
3. Solve for xx in 49x-250=-2849x−250=−28. x=\frac{222}{49}
x= 49 222
4. Substitute x=\frac{222}{49}x= 49 222 into y=50-7xy=50−7x.
y=\frac{128}{7} y= 7 128
5. Therefore, \begin{aligned}&x=\frac{222}{49}\\&y=\frac{128}{7}\end{aligned} x= 49 222 y= 7 128 Hope this helped!! :))