Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.



has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5



has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
Answer:
2^3·2^2 = 2^3+2 = 2^5
Step-by-step explanation:
Diego was trying to write 2^3 · 2^2
He wrote 2^3·2^2 = 2^3*2 = 2^6
But this is wrong because when bases are same exponents are added.
This is the law of exponents.
The correct form would be
2^3·2^2 = 2^3+2 = 2^5
For understanding it better we can write it like this
2^3·2^2 =
There are 3 two and 2 twos .When totaled there are 5 two not 6 twos.
Answer:

Step-by-step explanation:
Required
The equation of the ellipse
This is calculated as:

Where:
---- height
--- width
So:



Answer:
Sorry need points
Step-by-step explanation:
Answer:
y= -2
Step-by-step explanation:
Please see attached picture for full solution.
(From the 4th to 5th line, I multiplied both sides by 8)