Answer:
n=-4 x=-7
Step-by-step explanation:
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
Answer:
$25
Step-by-step explanation:
b= 45
x= number of hours
y= amount charged
Answer:
D
Step-by-step explanation:
Substitute the f(x) and g(x) into f/g
![\frac{\sqrt[3]{3x} }{5x+2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%7D%20%7D%7B5x%2B2%7D)
To find the domain,
Get the denominator of the fraction so 5x + 2 and equal it to 0 and find x
5x + 2 = 0
5x = -2
x = 
Therefore it's D
