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vekshin1
3 years ago
9

Please Help me i can't figure it out!!!!!!!

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Refer to the attachment

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Write all the factors of 9 . Use commas to separate them.rtth
Rasek [7]

Answer:

1, 3, 9

Step-by-step explanation:

the nine can be divided by those three numbers and no more

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3 years ago
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Between 3 P.M and 3:30 P.M., the minute hand of a clock moves 180 degrees. How many degrees does the hour hand move during that
AURORKA [14]

Answer:

Between 3 P.M. and 3:30 P.M the hour hand moves 15°.

Step-by-step explanation:

The rotation of the minute hand of a clock between 3 P.M. and 3:30 P.M. is from the the 12 hour mark to the 6 hour mark which is half of one complete cycle

One complete cycle of clock rotation = 360° = 12 hours

Therefore, the hour hand rotates 360/12 = 30° for each hour

Given that the time between 3 P.M. and 3:30 P.M. is 30 minutes = 1/2 an hour

The rotation of the hour hand between 3 P.M. and 3:30 P.M = Half the rotation for 1 hour

∴ The rotation of the hour hand between 3 P.M. and 3:30 P.M = 30°/2 = 15°

Between 3 P.M. and 3:30 P.M the hour hand moves 15°.

4 0
3 years ago
1<br> 1<br> 8 x 1,000) + (3 x 100) + (2 x 1) + (4 x 10) + (7 X 1000
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Answer:

8,324,700.0

Step-by-step explanation:

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3 years ago
Answer for brainilest and 11 points
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Top right corner

Step-by-step explanation:

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3 years ago
A company is replacing cables with fiber optic lines in rectangular casing BCDE. If segment DE = 3 cm and segment BE = 3.5 cm, w
Simora [160]

Answer: 3.66 cm

Step-by-step explanation: Given a rectangular casing BCDE with segment DE = 3 cm and segment BE = 3.5 cm.

The area A of a rectangle is length multiply by width.

Where length L = 3.5 cm and

width W = 3 cm

Area A = 3.5 × 3 = 10.5 cm^2

The pipe that will fit the fiber optic line is in cylindrical shape. Where area of a cylinder = πr^2.

But area A = 10.5. Substitute the values for the area of the cylinder

10.5 = πr^2

10.5 = 3.143 × r^2

Make r^2 the subject of formula

r^2 = 10.5/3.143

r = sqrt ( 3.34225 )

r = 1.828

Diameter = 2 × radius

Diameter = 2 × 1.829

Diameter = 3.656 cm

Therefore, the smallest diameter of pipe that will fit the fiber optic line is 3.66 cm approximately.

8 0
4 years ago
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