Answer:
1/6
Step-by-step explanation:
-3/4 - (-1/2) = - 1/4
-2/3 - 5/6 = - 3/2
-1/4 ÷ -3/2
Answer:
Todd has 540540 songs in his playlist.
Vlad has 270270 songs in his playlist.
Becca has 162162 songs in her playlist.
Step-by-step explanation:
# of songs Todd has = T
# of songs Vlad has = V
# of songs Becca has = B
1) Todd has twice as many songs in his playlist as Vlad:
T=2V
2) Becca has three times as many songs in her playlist as Todd:
B=3T
3) All three people have a total of 243243 songs in their playlists:
T+V+B=243243
Because T=2V then you can substitute T as 2V in the second equation:
B=3(2V)
B=6V
Now in the final equation, you can substitute everything for V:
2V+V+6V=243243
9V=243243
V=27027
Now substitute for T:
T+1/2T+3T=243243
9/2T=243243
T=54054
Now substitute for B:
1/3B+1/6B+B=243243
3/2B=243243
B=162162
Check answers:
27027+54054+162162=243243
243243=243243
Answer:
I believe that the answer is 4.13 weeks
Step-by-step explanation:
Since she already has $52 you can automatically start by doing:
$350 - $52 = $298
Since she works 8 hours a week and earns $9 per hour:
8 hours x $9 = $72
Then, take $298 ÷ $72 = 4.13 or about 4 weeks
I divide 298 by 72 because $72 is how much she will earn per week, and by dividing this number by the total amount that she has left to pay narrows it down to about how long she has to save for.
Hope this helps!!
The percentage of tardiness among the 102 pupils is 2.94.
<h2>Calculation of the percentage</h2>
According to the query,
Course A: Total number of students = 102
Number of tardy students = 3
Percent of students tardy in course A = (number of tardy students/total
number of students) * 100
=(3/102)*100
= 2.941
≈2.94
In case of course B: Total number of students = 85 & tardy student = 5
So, the percent of tardy student = (5/85)*100 = 5.88 %
Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.
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According to the statement 160 books were given to the class.
The correct option is C.
<h3>What is linear equation?</h3>
One or two variables make up a linear equation. Neither the numerator nor the denominator of a fraction can be a variable in a linear equation raised to a power higher than 1. All of the points on a coordinate grid sit on the same line when you identify the values that together make a linear equation true and plot those values.
<h3>According to the given information:</h3>
Let the no. of students be s:
Let the no. of books be b:
Given that there will be 20 books left after each student selects 4 books,
b = 4s + 20
And the remaining students take 5 books each, therefore b=5(s3), even if 3 pupils choose not to take a book.
comparing the value b
4s+20=5(s−3)
4s+20=5s−15
s=20+15
s=35
To do this, change the value of s in b=4s+20 to what is shown below:
b=4(35)+20
b=140+20
b=160
160 books were given to the class.
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