First of all, we can factor a factor of
from all terms:
![5 (3u^4-4u^3-7u^2)](https://tex.z-dn.net/?f=%205%20%283u%5E4-4u%5E3-7u%5E2%29%20)
Then, we can factor
from all terms:
![5u^2 (3u^2-4u-7)](https://tex.z-dn.net/?f=%205u%5E2%20%283u%5E2-4u-7%29%20)
To factor the quadratic expression in parenthesis, we must find its roots, which are
and
. This implies
![3u^2-4u-7 = 3(u+1)(u-\frac{7}{3})](https://tex.z-dn.net/?f=%203u%5E2-4u-7%20%3D%203%28u%2B1%29%28u-%5Cfrac%7B7%7D%7B3%7D%29)
So, the complete factorization is
![5u^2 \cdot 3(u+1)(u-\frac{7}{3}) = 15u^2(u+1)(u-\frac{7}{3})](https://tex.z-dn.net/?f=%205u%5E2%20%5Ccdot%203%28u%2B1%29%28u-%5Cfrac%7B7%7D%7B3%7D%29%20%3D%2015u%5E2%28u%2B1%29%28u-%5Cfrac%7B7%7D%7B3%7D%29%20)
Answer:
(x+4)(x-3)
Step-by-step explanation:
x^2+x-12
This equation has the given solutions of -4,3
Answer:
perpendicular lines
Step-by-step explanation:
Answer:
x=12
Step-by-step explanation:
3x-6=30
plus 6 both sides
3x=36
divide 3 both sides
x=12
I=Lmv
m=i/Lv
Just divide the other two