All categories

3 years ago

Write an equation of the function

Mathematics

1 answer:

ohaa [14]3 years ago

5 0

Answer:

g(x) = |x-3| -4

Step-by-step explanation:

to shift right by 3, subtract three from x inside the absolute value.

to shift down by 4, subtract 4 outside of the absolute value.

g(x) = |x-3| -4

You might be interested in

1. Factor the expression over the complex numbers.

zepelin [54]

1. (x² + 24) factors as the difference of two squares (x² - (-24)) where -24 is the square of the complex number i√24 = 2i√6. The factoring is
(x - 2i√6)(x + 2i√6)

2. The square of half the coefficient of the x-term needs to be added: 4.5² = 20.25
This number goes in both boxes.

3. This is the square of (y² +20), so the factorization is similar to that for problem 1.
y⁴ + 40y² + 400 = (y² + 20)² = (y -2i√5)²(y +2i√5)²

8 0

3 years ago

What is the relation between 1 and 2?

Tju [1.3M]

Answer:

Supplementary and Linear Pair

Step-by-step explanation:

The angles 1 and 2 form 180 degrees. That is the definition of a Supplementary Angle and Linear Pair.

4 0

4 years ago

-2|5x+3|>=4 i dont have the bigger equal simbols , please help me with this question ;((

ipn [44]

Step-by-step explanation:

-2|5x + 3| >= 4

|5x + 3| <= -2

Since absolute value is never negative, there are no real values for x.

6 0

3 years ago

1) What is the GCF for the polynomial 4x3 - 2x2y?

Dafna1 [17]

(1)the GCF for the polynomial $4x^3 - 2x^2y$

4x^3 = 2*2* x* x* x

2x^2y = 2*x*x*y

Greatest common factor is $2*x*x = 2x^2$

(2) the GCF for the polynomial $8x^4y + 6x^2y^2$

$8x^4y = 2*2*2*x*x*x*x*y$

$6x^2y^2 = 3*2*x*x*y*y$

GCF is $2*x*x*y=2x^2y$

(3) the GCF for the polynomial $12x^3y^2 - 20x^5y^3$

$12x^3y^2 = 2*2*3*x*x*x*y*y$

$20x^5y^3=5*2*2*x*x*x*x*x*y*y*y$

GCF is $2*2*x*x*x*y*y= 4x^3y^2$

(4) the GCF for the polynomial $-10x^3y^4 - 16x^5y^2$

$-10x^3y^4 =-2*5*x*x*x*y*y*y*y$

$-16x^5y^2=-2*2*2*2*x*x*x*x*x*y*y$

GCF is $-2*x*x*x*y*y= -2x^3y^2$

3 0

3 years ago

Read 2 more answers

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago