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nalin [4]
3 years ago
14

What are Pythagorean triplets?Write five examples​

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

Pythagorean triplet are the values of hypotenuse, base and perpendicular which tend to represent a right-angled triangle. Integral solutions to the Pythagorean Theorem, a2+b2=c2 are called Pythagorean triplet which contains three positive integers a,b,c where a<b<c.

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Which choice shows +=7
V125BC [204]

Answer:

y=-x +7 is the slope-intercept form and the graph is shown in the attachment.

Step-by-step explanation:

The given equation is

x + y = 7

We solve for y to get:

y =  - x + 7

This is now of the form, y=mx+c

This is called the slope-intercept form.

Since the slope is negative, the graph slopes backwards. Also the y-intercept is 7, so the graph will intersect the y-axis at 7

7 0
3 years ago
2. Let Y denote the average starting salary for 2014 U.S. college graduates, measured in dollars. Suppose that the average annua
Dafna11 [192]

Answer:

Average salary: 56

Standard deviation of the salary: 8

Step-by-step explanation:

$56,000 dollars is 56 thousand dollars.

$8,000 is 8 thousand dollars.

The mean is the average. So the average, measured in thousands of dollars, is 56.

The standard deviation is $8,000. So, the standard deviation measured in thousands of dollars, is 8.

5 0
3 years ago
Help with these 4 questions please and thanks!!!
HACTEHA [7]
1. The radius is ✓33≈C
2. Center: (-2,3)
Radius: ✓23
3. Equation: (x+3)^2+(y+5)^2=125
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8 0
3 years ago
Find the positive base $b$ in which the equation $5_b \cdot 23_b = 151_b$ is valid.
DanielleElmas [232]

Answer:

b=7

Step-by-step explanation:

We want to determine the positive base b in which:

5_b \cdot 23_b = 151_b

The easiest way to approach this is to convert all the numbers to base 10.

5_b=5Xb^0=5\\23_b =(2Xb^1)+(3Xb^0)=2b+3\\151_b=(1Xb^2)+(5Xb^1)+(1Xb^0)=b^2+5b+1\\Therefore:\\5_b \cdot 23_b = 151_b\\5(2b+3)=b^2+5b+1\\10b+15=b^2+5b+1\\b^2+5b+1-10b-15=0

b^2-5b-14=0

Next, we factorize the resulting expression.

b^2-5b-14=b^2-7b+2b-14=0\\b(b-7)+2(b-7)=0\\(b-7)(b+2)=0\\b-7=0\: or \: b+2=0\\b=7\: or \: b=-2

The positive value of b for which the equality hold is 7.

3 0
2 years ago
Can someone tell me what is the slope of the line that includes points (4,-10) and (6,8)
miss Akunina [59]

Answer: hmmm no!

Step-by-step explanation:

3 0
3 years ago
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