Answer:
Second class have higher marks and greater spread.
Step-by-step explanation:
First box plot represents class first. From the first box plot, we get
Second box plot represents class second. From the second box plot, we get
First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.
Second class has greater range and greater inter quartile range. It means data of second class has greater spread.
Therefore, second class have higher marks and greater spread.
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Answer:
Sin(F) = 12/13
Cos(F) = 5/13
Tan(F) = 12/5
Step-by-step explanation:
Sin = Opp./Hypo, Cos = Adj./Hypo. and Tan = Opp./Adj.
So
Sin(F) = Opp./Hypo = 12/13
Cos(F) = Adj./Hypo = 5/13
Tan(F) = Opp./Adj. = 12/5
Answer:
20x² - 43xw + 21w²
Step-by-step explanation:
We use FOIL to expand the expression:
F - First
4x(5x) = 20x²
O - Outside
4x(-7w) = -28xw
I - Inside
-3w(5x) = -15xw
L - Last
-3w(-7w) = 21w²
20x² - 28xw - 15xw + 21w²
Combine like terms and add up using correct signs and you should get your answer.
Answer:
Step-by-step explanation:
75x + -300 = 25x + 200
Reorder the terms:
-300 + 75x = 25x + 200
Reorder the terms:
-300 + 75x = 200 + 25x
Solving
-300 + 75x = 200 + 25x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-25x' to each side of the equation.
-300 + 75x + -25x = 200 + 25x + -25x
Combine like terms: 75x + -25x = 50x
-300 + 50x = 200 + 25x + -25x
Combine like terms: 25x + -25x = 0
-300 + 50x = 200 + 0
-300 + 50x = 200
Add '300' to each side of the equation.
-300 + 300 + 50x = 200 + 300
Combine like terms: -300 + 300 = 0
0 + 50x = 200 + 300
50x = 200 + 300
Combine like terms: 200 + 300 = 500
50x = 500
Divide each side by '50'.
x = 10
Simplifying
x = 10
