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Komok [63]
3 years ago
8

Out of the last 50 guests, only 1 of them brought a coupon for free admission to the carnival. if there are 1,500 guests expecte

d this weekend, how many can we expect will recieve free admission?
Mathematics
1 answer:
Oliga [24]3 years ago
8 0
30 people have free admission


1500 divided by 50= 30
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Step-by-step explanation:

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Use the information from the polling agency to determine the sample size needed to construct a 95% confidence interval with a ma
Ber [7]

Answer:

the sample size n= 771

sample proportion is p = 1/2

Step-by-step explanation:

<u>Step1:</u>-

marginal error formula is \frac{2S.D}{\sqrt{n} }

but if 'n' is sample size then n = \frac{1}{(margin error)^{2} }

Given margin error is 36% = 0.036

n= \frac{1}{(0.036)^2}

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<u>Step 2</u>:-

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\frac{36}{100}  = \frac{2\sqrt{p(1-p)} }{\sqrt{771} }

after simplification, we get

\sqrt{p(1-p)} = \frac{1}{2}

squaring on both sides, we get

p(1-p) = \frac{1}{4}

multiply 'p' inside

p-p^{2} =\frac{1}{4}

cross multiplication '4' and simplify

4p^{2} -4p +1 =0 ........(1)

finding 'p' value

The equation (1) is of the form (a-b)^{2} = a^{2} -2ab+b^{2}

(2p)^{2} -2(2p)(1)+1^{2} = (2p-1)^2

(2p-1)^2 =0

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<u>conclusion</u>:-

The sample size is 771

the sample proportion is p = \frac{1}{2}

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