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3 years ago

8

Out of the last 50 guests, only 1 of them brought a coupon for free admission to the carnival. if there are 1,500 guests expecte

d this weekend, how many can we expect will recieve free admission?

1 answer:

Oliga [24]3 years ago

8 0

30 people have free admission

1500 divided by 50= 30

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Write 2x+3y=6 in slope intercept form

Leokris [45]

Slope-intercept form:
y=mx+b

m=slope
b=y-intercept

2x+3y=6
3y=-2x+6
y=-2/3 x+6/3
y=-2/3 x+2

Answer: the line in slope-intercept form would be:
y=-2/3 x+2

3 0

3 years ago

In 2013, the population of the state of New York was approximately 19.65 million, and the population of New York City was 8,406,

maks197457 [2]

Population of the state of New York is 19.65 million.
Million is equal to 1*10^6
So 19.65*10^6

Population of New York city is 8,406,000.
It is equal to 8.406*10^6

Therefore people in New York state did not in New York city is,
19.65*10^6 - 8.406*10^6
11.244*10^6
1.1244*10^7

7 0

3 years ago

There is a total of 2,512 people attending the fun fair. 5/8 of sttemdees are students and 1/4 of attendees are parents. the res

kvv77 [185]

Answer:

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of people attending the fun fair = 2,512

Fraction of people attending the fun fair that are students = 5/8

Fraction of people attending the fun fair that are parents = 1/4

Rest of the people attending the fun fair lives in the neighborhood

2. Let's calculate the number of students, parents and people living in the neighborhood

Students:

Fraction of people attending the fun fair that are students = 5/8

5/8 * 2,512 = 1,570

1,570 of the people attending the fun fair are students

Parents:

Fraction of people attending the fun fair that are parents = 1/4

1/4 * 2,512 = 628

628 of the people attending the fun fair are parents

People living in the neighborhood

2,512 - 1,570 - 628 = 314

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

8 0

3 years ago

A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol

iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let $x_1$ be the number of widgets sold and $x_2$ be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

$x_1+x_2=350...(1)$

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

$35x_1+22x_2=9,000...(2)$

From equation (1), we will get:

$x_2=350-x_1$

Substitute this value in equation (2):

$35x_1+22(350-x_1)=9,000$

$35x_1+7,700-22x_1=9,000$

$13x_1+7,700=9,000$

$13x_1+7,700-7,700=9,000-7,700$

$13x_1=1,300$

$\frac{13x_1}{13}=\frac{1,300}{13}$

$x_1=100$

Therefore, the company sold 100 widgets.

Substitute $x_1=100$ in equation (1):

$100+x_2=350$

$100-100+x_2=350-100$

$x_2=250$

Therefore, the company sold 250 gizmos.

3 0

3 years ago

Read 2 more answers

What is the solution of 10=|7-3x|

Tom [10]

$10=|7-3x| \\ 7-3x=10 \vee 7-3x=-10\\ 3x=-3 \vee 3x=17\\ x=-1 \vee x=\dfrac{17}{3}$

5 0

3 years ago