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mote1985 [20]
3 years ago
6

4) Solve each pair of simultaneous equations.

Mathematics
1 answer:
Mkey [24]3 years ago
7 0
4) a. x+y=1–(1)
y=2x-8—(2)
(2) into (1)
x+(2x-8)=1
3x-8=1
3x=1+8
x=9/3
x=3—(3)
(3) into (2)
y=2(3)-8
y=-2

ans x=3, y=-2

b. x+y=19—(1)
y=5x+1—(2)

(2) into (1)

x+(5x+1)=19
6x+1=19
6x=19-1
x=18/6
x=3—(3)

(3) into (2)

y=5(3)+1
y=16

ans x=3, y=16

c.x+y=-2—(1)
y=x-10—(2)

(2) into (1)

x+(x-10)=-2
2x-10=-2
2x=-2+10
x=8/2
x=4–(3)

(3) into (2)
y=4-10
y=-6

ans x=4, y=-6


5) 3x=y—(1)
x=y-16–(2)

(2) into (1)

3(y-16)=y
3y-48=y
2y=48
y=48/2
y=24–(3)

(3) into (2)

x=24-16
x=8

ans x=8, y=24
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N - 4 = 3n + 6<br> Plz help me if possible no pics
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Answer:

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Step-by-step explanation:

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Let f(x)=(x-2)^3+8 Find the inverse of f(x). Please show steps in written form would be gladly appreciated
Tatiana [17]

Hello from MrBillDoesMath!

Answer:

(x-8)^(1/3) +2

Discussion:

To find the inverse of a function swap the values of x and y in the original equation y = (x-2)^3 +8  and solve for y.

y = (x-2)^3 +8          =>  original function. swap x and y values

x = (y-2)^3 + 8        =>  subtract 8 from both sides

x - 8  = (y -2)^3        =>  take cube root of both sides

(x-8)^(1/3) = y - 2     => add 2 to both sides

(x-8)^(1/3) +2 = y      => y is the inverse



Thank you,

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