F’(x)= -akxsinkx
F’’(x)= -a(kx)^2coskx
I’m really sorry if the answer turned out wrong but I tried my best!
If I am rolling a single dice what is the probability of rolling a number that is divisible by 2 and 3? The only number divisible by 2 and 3 is 6. So, would the answer be 1 out 6 or 1/6
X^5 (X to the fifth power) - 4 (x^5 - 4)
Answer:
D.) 8:00
It’s a geometric problem so when plugged in you get answer D