All categories

2 years ago

(y4 – y3 + 2y2 + y – 1) ÷ (y3 + 1)

Mathematics

1 answer:

Svetradugi [14.3K]2 years ago

3 0

FIRST (y x 4 - y x 3 + 2y x 2 + y -1) / (y x 3 + 1)
SECOND (4y-3y+4y+y-1) / (3y+1)
THIRD (6y-1) OVER (3y+1)

You might be interested in

30 points for anyone that can solve the question

marusya05 [52]

The solution to this problem is 5/2a^2b^5

5 0

3 years ago

PLEASE ANSWER QUICK One year, the population of a city was 164,000. Several years later it was 182,040. Find the percent increas

Katena32 [7]

Answer:

There was an 11% increase.

Step-by-step explanation:

The formula to find a percent increase is this: (original amount - new amount / original amount) * 100

If you fill in the formula, you get this:

(164,000 - 182,040 / 164,000) * 100

Solve:

(-18,040 / 164,000) * 100 ---> If the number being divided is negative, find the absolute value.

(18,040 / 164,000) * 100 =

0.11 * 100

11%

5 0

3 years ago

Which equation can you use to solve for figure shown?

DIA [1.3K]

Hey mate

Here is ur answer ...

I hope it'll help ....

4 0

3 years ago

Read 2 more answers

What is the solution to the equation?

Oxana [17]

ANSWER

EXPLANATION

The given equation is

$\frac{ - 3d}{ {d}^{2} - 2d - 8} + \frac{3}{d - 4} = \frac{ - 2}{d + 2}$

Factor the first fraction to get,

$\frac{ - 3d}{(d + 2)(d - 4)} + \frac{3}{d - 4} = \frac{ - 2}{d + 2}$

Multiply through by (d+2)(d-4)

$- 3d + 3(d + 2) = - 2(d - 4)$

Expand:

$- 3d + 3d + 6 = - 2d + 8$

$6 = - 2d + 8$

$6 - 8= - 2d$

$- 2 = - 2d$

divide both sides by -2

$d = 1$

7 0

3 years ago

Read 2 more answers

A square on a coordinate plane has the points A(0, 0), B(0, 5), C(5, 5) and D(5, 0). If Square ABCD is rotated about the origin

Georgia [21]

Answer:

B. 5 units

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, dilation, rotation or translation.

If a point X(x,y) is rotated about the origin 180 degrees clockwise the new point is at X'(-x, -y).

If the square with vertices at A(0, 0), B(0, 5), C(5, 5) and D(5, 0) is rotated about the origin 180 degrees clockwise the new points are at A'(0, 0), B'(0, -5), C'(-5, -5), D'(-5, 0)

A square has four equal sides. The distance between two points $X(x_1,y_1)\ and\ Y(x_2,y_2)$ is:

$|XY|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Hence:

$|A'B'|=\sqrt{(0-0)^2+(-5-0)^2} =5$

3 0

3 years ago