Answer: 1: 5(3x+4)
2: 6(x2+4x−3)
3: 5x(4x2−3x+2)
4: 4n2(4n2-3)
Step-by-step explanation:
Answers:
- Pizza Uno = $5.25
- Pizza Duo = $5.60
Those are the costs for a whole small pizza.
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Explanation:
Let
- x = cost of whole small pizza from Pizza Uno
- y = cost of whole small pizza from Pizza Duo
x and y are some dollar amount, so they cannot be negative numbers. It also doesn't make sense to have them be 0 either. So we'll make them positive.
2/3 of x is equal to 3.50 as the first sentence mentions. This forms the equation (2/3)*x = 3.50
Multiply both sides by the reciprocal of 2/3 to isolate x
(2/3)*x = 3.50
(3/2)*(2/3)*x = (3/2)*3.50
x = 5.25
Pizza Uno charges $5.25 for a whole small pizza.
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Pizza Duo charges $4.20 for 3/4 of a small pizza, meaning the equation we need to solve is
(3/4)y = 4.20
We'll use the same idea as the last equation to get...
(3/4)y = 4.20
(4/3)*(3/4)y = (4/3)*4.20
y = 5.60
Pizza Duo charges $5.60 for a whole small pizza.
Pizza Uno is the better deal (assuming both pizzas taste the same or you don't have a preference for either). You would save $5.60 - $5.25 = $0.35 = 35 cents.
Answer:
1. 80
2. 2400
Step-by-step explanation:
1. what is the change in Dan's total pay for each copy of math is fun he sells?
2. what is Dan's total pay if he doesn't sell any copies of math is fun?
Given
y=80x + 2400
When x=0
y=80(0)+2400
=0+2400
=2400
When x=1
y=80x + 2400
=80(1) + 2400
=80+2400
=2480
change in Dan's total pay for each copy of math is fun he sells is
= 2480 - 2400
=80
2. Dan's total pay if he doesn't sell any copies of math is fun?
y=80x+2400
When x=0
y=80(0)+2400
=0+2400
=2400
a linear combination can be:
(a + b)*(4x + 15y) = a*12 + b*15
<h3>How to solve the given system of equations:</h3>
Here we have the system of equations:
(2/3)*x + (5/2)*y = 15
4x + 15y = 12
To solve the system of equations, we first need to isolate one of the variables in one of the equations, I will isolate x on the second equation.
4x = 12 - 15y
x = (12 - 15y)/4
Now we can replace that in the other equation:
(2/3)*x + (5/2)*y = 15
(2/3)* (12 - 15y)/4 + (5/2)*y = 15
Now we can solve that for y.
2 - (10/4)*y + (5/2)*y = 15
2 = 15
That is a false equation, then we conclude that the system of linear equations has no solutions.
This means that the two lines are parallel lines, then a linear combination can be:
(a + b)*(4x + 15y) = a*12 + b*15
Where a and b are two real numbers.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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