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erastova [34]
2 years ago
6

Can someone explain this to me and how you do it. Also please help me get the answer and show some work on how you got it!

Mathematics
1 answer:
navik [9.2K]2 years ago
3 0

Answer:

Step-by-step explanation:

5\frac{1}{3} ÷ \frac{4}{7} = \frac{16}{3} ÷ \frac{4}{7}

= \frac{16}{3} × \frac{4}{7}= \frac{64}{21}

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Please help I'm begging
Elina [12.6K]
The figure is made up of a cone and a cylinder.

Diameter = 16 ft
radius = 16÷2 = 8ft

Volume of the cone = 1/3bh
Volume of the cone = \frac{1}{3}  \pi  r^{2} h
Volume of the cone =  \frac{1}{3} \pi 8^{2}(6) = 402.12

Volume of the cyclinder = bh
Volume of the cylinder = \ \pi r^{2} h
Volume of the cylinder = \ \pi 8^{2}(4) = 1206.37

Total = 402.12 + 1206.37 = 1608.49 cubic feet

6 0
3 years ago
I just want you to know have a good day
valentinak56 [21]

Answer:

Thank you very much :) needed that

6 0
3 years ago
Read 2 more answers
What is 27÷2356 with the work
Charra [1.4K]
Math answers to fraction 2356 divided by 27 can be calculated as follows.

2356/27 math problems division = 87.2592592593. Therefore 87.2592592593 to 2 decimal places= 87.26

2356/27 divided by 2 » (2356/27) ÷ 2 » 87.2592592593 ÷ 2 = 43.6296296296 .

5 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
How to do this question plz ​
MrRissso [65]

Answer:

10:1

90 red counters

30 blue

1/3 of 90 =30

80% of 30 =24

90-30 =60 remaining red counters

30-24 =6 remaining blue counters

= 60:6 simplest form is 10:1

8 0
3 years ago
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