A) because when they are equal it means that their y has the same value, which means their intersection point.

B) You should take all integers from (-2, 2) which are: -2, -1, 0, 1, 2 and put them one by one in the example:
x = -2
y1 = 4^-(-2) = 4^2 = 16
y2 = 2^(-(-2) + 1) = 2^(2+1) = 2^3 = 8
y1 ≠ y2 => so x=-2 isn't our answer
-------------------------------------------------------
x = -1
  y1 = 4^-(-1) = 4^1 = 4
y2 = 2^(-(-1) + 1) = 2^(1+1) = 2^2 = 4
y1 = y2   =>   so our answer will be x = -1
-------------------------------------------------------
x = 0
  y1 = 4^-(0) = 4^0 = 1
y2 = 2^(-(0) + 1) = 2^(0+1) = 2^1 = 2
y1 ≠ y2 => so x=0 isn't our answer
--------------------------------------------------------------
x = 1
  y1 = 4^-(1) = 4^(-1) = 1/4
y2 = 2^(-(1) + 1) = 2^(-1+1) = 2^0 = 1
y1 ≠ y2 => so x=1 isn't our answer
--------------------------------------------------------------
x = 2
  y1 = 4^-(2) = 4^(-2) = 1/16
y2 = 2^(-(2) + 1) = 2^(-2+1) = 2^(-1) = 1/2
y1 ≠ y2 => so x=2 isn't our answer

Which means that our final answer is: x=-1

C) You should draw both graphics, and their intersection point (x) will be the answer.

I hope it helped.

6 0

3 years ago

A blind man wanders under a door into an empty room. After running into the walls repeatedly for a while, it stops to think and

Nostrana [21]

From the side where the man is located in the 10' by 12' rectangular room, we have;

A) 0.046

B) The average time to escape in first attempt is approximately 605.02 seconds

<h3>Which concept can be used to find the odds and time of escape?</h3>

A) From The given diagram, we have;

Width of the door = 10 - 6 - 2 = 2

Therefore, the door is 2 feet wide

Distance, d1, from the man to the side of the door closer to him is given by Pythagorean theorem as follows;

d1 = √(6² + 7²) = √(85)

From the furthest side of the door to the man, we have;

d2 = √(7² + 8²) = √(113)

According to the law of cosines, we have;

2² = 85+113 - 2×√(85)×√(113) cos(A)

Where angle A is the angle formed by the lines from the man to the closer and farther sides of the door.

2×√(85)×√(113) cos(A) = 85+113 - 2²

A = arccos((85+113 - 2²)/(2×√(85)×√(113)))

A = arccos (194/(2×√(9605)) ≈ 8.213°

The angle of the possible directions in which the man can turn is 180°.

Therefore;

The probability, P(E), of escaping in the first move is therefore;

P(E) = 8.213°/180° ≈ 0.046

B) Given that the man escapes in the first move, the shortest and longest distances the man moves are;

d1 = √(85) and d2 = √(113)

Speed of the man, v = 0.5 cm/sec

Therefore by unit conversion function of a graphing calculator;

v = (25/1524) ft./sec

The times taken are;

t1 = √(85)/(25/1524) ≈ 562.023

t2 = √(113)/(25/1524) ≈ 648.014.

Average time, t = (t1 + t2)/2

Which gives;

t = (562.023 + 648.014)/2 ≈ 605.02

The average time it takes the man to escape in first move is t ≈ 605.02 seconds.

Learn more about Pythagorean theorem and probability here:

brainly.com/question/27180985

brainly.com/question/654982

brainly.com/question/24756209

#SPJ1

3 0

1 year ago