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2 years ago

Need helpppppppppppppppppp

Mathematics

2 answers:

adoni [48]2 years ago

8 0

Your answer would be the 4th one

Rus_ich [418]2 years ago

6 0

Answer:

A child experiencing emotional.........

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a lumber yard has a scrap sheet of plywood that is 4 1/2 feet by 2 5/6 feet. what is the area of the plywood

nikklg [1K]

A = L * W
A = 4 1/2 * 2 5/6
A = 9/2 * 17/6
A = 153/12 or 12 3/4 ft <==

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3 years ago

Hiiiiiiiiiiiiiiiiiiiiiiiiii

valentina_108 [34]

Answer:

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Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Use the bionomial theorem to write the binomial expansion

MaRussiya [10]

Answer:

$\left(\frac{x}{2} + 3 y\right)^{4}=\frac{x^{4}}{16} + \frac{3}{2} x^{3} y + \frac{27}{2} x^{2} y^{2} + 54 x y^{3} + 81 y^{4}$

Step-by-step explanation:

$\left(\frac{1}{2}x+3y \right)^4=\left(\frac{x}{2}+3y \right)^4\\$

Binomial Expansion Formula:

$(a+b)^n=\sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$ , also $\binom{n}{k}=\frac{n!}{(n-k)!k!}$

We have to solve $\left(\frac{x}{2} + 3 y\right)^{4}=\sum_{k=0}^{4} \binom{4}{k} \left(3 y\right)^{4-k} \left(\frac{x}{2}\right)^k$

Now we should calculate for $k=0, k=1, k=2, k=3 \text{ and } k =4;$

First, for $k=0$

$\binom{4}{0} \left(3 y\right)^{4-0} \left(\frac{x}{2}\right)^{0}=\frac{4!}{(4-0)! 0!}\left(3 y\right)^{4} \left(\frac{x}{2}\right)^{0}=\frac{4!}{4!}(81y^4)\cdot 1 =81 y^{4}$

It is the same procedure for the other:

For $k=1$

$\binom{4}{1} \left(3 y\right)^{4-1} \left(\frac{x}{2}\right)^{1}=54 x y^{3}$

For $k=2$

$\binom{4}{2} \left(3 y\right)^{4-2} \left(\frac{x}{2}\right)^{2}=\frac{27}{2} x^{2} y^{2}$

For $k=3$

$\binom{4}{3} \left(3 y\right)^{4-3} \left(\frac{x}{2}\right)^{3}=\frac{3}{2} x^{3} y$

For $k=4$

$\binom{4}{4} \left(3 y\right)^{4-4} \left(\frac{x}{2}\right)^{4}=\frac{x^{4}}{16}$

You can perform the calculations, I will not type everything.

The answer is the sum of elements calculated.

Just organizing:

$\left(\frac{x}{2} + 3 y\right)^{4}=\frac{x^{4}}{16} + \frac{3}{2} x^{3} y + \frac{27}{2} x^{2} y^{2} + 54 x y^{3} + 81 y^{4}$

8 0

3 years ago

Read 2 more answers

Ok can someone help me?

liberstina [14]

Answer:just ask fr help

Step-by-step explanation:

7 0

3 years ago

Please hellllp !!! find the area of the figure below 7mm, 10.4mm ,15.3mm

beks73 [17]

Answer: 288.62

Step-by-step explanation:

5 0

2 years ago