This may be one of those questions that could take
more paper to ask than to answer.
Line-1 goes through (-4, 8) and (4,6) .
Its slope is (difference in 'y') / (difference in 'x')
Dif in 'y' = (6 - 8) = 2
Dif in 'x' = (4 - -4) = 8
Slope of Line-1 = 2/8 or 1/4
Line-2 goes through (-1, 1) and (3, 5)
Its slope is (difference in 'y') / (difference in 'x')
Dif in 'y' = (5 - 1) = 4
Dif in 'x' = (3 - -1) = 4
Slope of Line-2 = 4/4 = 1
Slope of Line-1 = 1/4
Slope of Line-2 = 4
The slopes of the lines are different.
They can't be parallel, and they can't be the same line.
They must intersect in one point, and only one point.
That means the pair of equations has exactly one (1) solution.
X=-3x+20
Add 3x to both sides to move the -3x over
4x=20
Then do 20 divided by 4
X=5
Answer:
y=2x-19
Step-by-step explanation:
I'm guessing you mean slope intercept form y=mx+b
If so, first you would have to find the slope of the line
To do that, use the formula y2-y1/x2-x1
Remember you can pick any coordinate pair for this
I will pick 1=y2 -5=y1 10=x2 and 7=x1
When I put that in the equation I get 1-(-5)/10-7
Overall I get 6/3, or 2
Now to find the y intercept, you plug in the slope and one of the coordinates(any is fine)
I will pick (10,1)
1=y and 10=x and 2=m
1=2(10)+b
this simplifies to 1=20+b
now subtract 20 from both sides and get -19 = b
Now you have your equation y=2x-19
Answer:
The first blank is Reflection across the line x=-3
The second blank is reflection across the line y=x
for Edumentum/PLATO
Step-by-step explanation:
I just did the test. I got it correct. Good luck to everyone else taking their finals rn :)
only in the 1st and 2nd quadrants, where sine is positive