Question

Use the quadratic formula to solve the equation x^2-3x+2=0

Answer 1

Answer:

x= 1, 2

Step-by-step explanation:

The quadratic formula is $x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$. Here a=1, b=-3, and c=2.

Substitute and you'll have:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{3+/-\sqrt{(-3)^2-4(1)(2)} }{2(1)}=\frac{3+/-\sqrt{9-8} }{2)}$

$\frac{3+/-\sqrt{1} }{2}=\frac{3+/-\sqrt{1} }{2}=\frac{3+/-1 }{2}= 2 , 1$