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3 years ago

8

Mr. Candy needs to purchase large bags of Snickers to sell in the school store. A bag of Snickers contains 72 Snicker bars. A ba

g of Snickers cost $23. How much should Mr. Candy sell the Snicker bars to make a profit of $49?

1 answer:

DiKsa [7]3 years ago

7 0

Answer:

70 cents each snickers bar

Step-by-step explanation:

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Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo

Shkiper50 [21]

Answer:

a) $P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335$

b) $P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452$

c) $P(X \geq 8) = 1-P(X$

d) $P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that $X \sim Poisson(\lambda=4)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda=4$ , $Var(X)=\lambda=2$ , $Sd(X)=2$

a. Compute both P(X≤4) and P(X<4).

$P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183$

$P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733$

$P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465$

$P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646$

$P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692$

b. Compute P(4≤X≤ 8).

$P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595$

$P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298$

$P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452$

c. Compute P(8≤ X).

$P(X \geq 8) = 1-P(X$

$P(X \geq 8) = 1-P(X$

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

$P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

4 0

3 years ago

Simplify the expression –2(p 4)2 – 3 5p. what is the simplified expression in standard form? –2p2 – 11p – 35 2p2 21p 29 –2p2 13p

Aleksandr-060686 [28]

The simplified expression of the provided equation in standard form is -2p²-11p-35. Option 1 is the correct option.

<h3>What is the simplified form of an expression?</h3>

Simplified form of an expression is the simplest way of expression the term, by applying the required operations of mathematics.

The expression which is need to be simplified is,

$-2(p +4)^2 - 3 +5p$

First of all, open the brackets, using the formula of whole square,

$-2(p^2 +16+8p) - 3 +5p\\-2p^2-32-16p-3+5p\\-2p^2-11p-35$

Hence, the simplified expression of the provided equation in standard form is -2p²-11p-35. Option 1 is the correct option.

Learn more about the simplified form here;

brainly.com/question/1597694

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2 years ago

The diameter of a circle is 16 in . Find its circumference in terms of pi?

77julia77 [94]

Answer:

Circumference of circle = πd = π × 16 =16 π in.

or

circumference of circle = 2πr = 2×π×8= 16 π in.

5 0

3 years ago

9. Sonia bought 5 shirts that cost $38.00 each. If the tax rate is 8.5%, how much did Sonia pay?

qaws [65]

The answer is A

8.5% sales tax + 38.00= $41.23 x 5 (shirts)= $206.15

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3 years ago

5b8c3<br> The degree of the monomial is?

KonstantinChe [14]

Answer:

<u>8</u>

Step-by-step explanation:

The given monomial is :

<u>5b⁸c³</u>

<u />

The degree of the monomial is the highest power to which a variable is raised to in the monomial. The greatest power in this case belongs to b⁸, which has a power of 8.

Hence, the degree of the monomial is <u>8</u>

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2 years ago