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juin [17]
1 year ago
10

Simplify the expression –2(p 4)2 – 3 5p. what is the simplified expression in standard form? –2p2 – 11p – 35 2p2 21p 29 –2p2 13p

13 4p2 37p – 67
Mathematics
1 answer:
Aleksandr-060686 [28]1 year ago
5 0

The simplified expression of the provided equation in standard form is -2p²-11p-35. Option 1 is the correct option.

<h3>What is the simplified form of an expression?</h3>

Simplified form of an expression is the simplest way of expression the term, by applying the required operations of mathematics.

The expression which is need to be simplified is,

-2(p +4)^2 - 3 +5p

First of all, open the brackets, using the formula of whole square,

-2(p^2 +16+8p) - 3 +5p\\-2p^2-32-16p-3+5p\\-2p^2-11p-35

Hence, the simplified expression of the provided equation in standard form is -2p²-11p-35. Option 1 is the correct option.

Learn more about the simplified form here;

brainly.com/question/1597694

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~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

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