For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
More can be learned about probability distributions at brainly.com/question/24802582
#SPJ1
Answer:
16
Step-by-step explanation:
First, we plug in -3 in place of x...
f(x) = 2(-3)^2 + (-3) + 1
Then, we simplify each indidvidual expression...
f(x) = 18 - 3 + 1
Finally, we add/subtract all the values to get our answer...
f(x) = 16
<span>{(–1, 3), (5, 3), (–6, 7), (9, 0)} is the correct answer.
I hope this helped!
</span>