Answer:
95% Confidence interval: (0.0429,0.0791)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 679
Number of anonymous websites, x = 42
![\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%20%3D%20%5Cdfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cdfrac%7B42%7D%7B679%7D%20%3D%200.0618)
95% Confidence interval:
![\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Cpm%20z_%7Bstat%7D%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
![z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96](https://tex.z-dn.net/?f=z_%7Bcritical%7D%5Ctext%7B%20at%7D~%5Calpha_%7B0.05%7D%20%3D%20%5Cpm%201.96)
Putting the values, we get:
![0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)](https://tex.z-dn.net/?f=0.0618%5Cpm%201.96%28%5Csqrt%7B%5Cdfrac%7B0.0618%281-0.0618%29%7D%7B679%7D%7D%29%20%3D%200.0618%5Cpm%200.0181%5C%5C%5C%5C%3D%280.0429%2C0.0791%29)
is the required confidence interval for proportion of all new websites that were anonymous.
Answer: 80,000
Step-by-step explanation: 8x(10x10x10x10)=8x10,000=80,000
That would equal 1/4:)
hope i helped chu out
A farm had 480 acres more wheat than corn. Let use "W" to represent the Wheat and let use "C" to represent the corn. Hence, we have below:
W=C+480
The farmers collected 80% of the wheat and 25% of the corn and the area of the wheat is 300 acres less than the area of the corn:
W-0.8W=C-0.25C+300
0.2W=0.75C+300
We have two equations, two unknowns:
0.2(C+480)=0.75C+300
0.2C+96=0.75C+300
0.55C=294
C=534.55
<span>There is no way to get an exact answer. It could be a really small rhombus, or a huge one, and still have a 46º angle there. You need at least one length of a segment.
Your problem could have errors that's why it can't be solved. You do not have to worry because it happens sometimes.
I hope it helps you.</span>