Answer:
Angle I = 90 degrees
Angle J = 61 degrees
Angle K = 29 degrees
Step-by-step explanation:
Angle I is given
We know that the angles in all triangles add up to 180. Since we are given that angle I is equal to 90 degrees, we now know that angle J + angle K = 90 degrees:
(5x+26) + (2x+15) = 90
Solve for X:
7x + 41 = 90
7x = 49
x = 7
Angle J = (5x + 26) = (5(7) + 26) = 61
Angle K = (2x + 15) = (2(7) + 15) = 29
Checking your work: 61 + 29 = 90
Answer:
i think geometry
Step-by-step explanation:
Answer:
- The area of rhombus JKLM is 48 units²
=====================================
<h3>Given </h3>
- Rhombus JKLM,
- Vertices at J(-2, -4), K(2, 2), L(6, -4), M(2, -10).
<h3>To find </h3>
<h3>Solution</h3>
We know that diagonals of rhombus are perpendicular to each other.
Hence its area is half the product of diagonals.
The diagonals are JL and KM and one of them is vertical and the other one horizontal since x- or y-coordinates are equal in pairs.
Let's find the length of diagonals, using the difference of coordinates:
- JL = 6 - (-2) = 8 units,
- KM = 2 - (-10) = 12 units.
Now find the area:
- A = JL*KM /2 = 8*12 / 2 = 48 units²
First one is 75/100 = x/80 with 60 free throws, second best is 70/100 = x/80 with 56 free throws, and last is 65/100 = x/80 with 52 free throws
Answer:
A = 62x^2
Step-by-step explanation:
This rect. prism has 6 faces, stemming from two each of the areas of the top, the end and the side of the prism.
top surface area: (2x)(3x) = 6x^2
end surface area: (2x)(5x) = 10x^2
side surface area: (3x)(5x) = 15x^2
Total surface area: A = 2(6x^2 + 10x^2 + 15x^2)
or: A = 2(31x^2) = 62x^2