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Nataly [62]
2 years ago
7

I use 1/12 of my salary to pay for rates and taxes,1/16 to pay for insurance and 5/6 to meet other expenses. if i have r320 left

of my monthly salary, calculate my yearly salary.​
Mathematics
1 answer:
omeli [17]2 years ago
6 0

The yearly salary after paying for taxes, insurances and other expenses is  r808.42.

<h3>What is the yearly salary?</h3>

The first step is to determine the total fraction used to pay for taxes, insurances and other expenses:

1/2 + 1/16 + 5/6

(48 + 6 + 80) / 96 = 134 / 96=  1 19/48

Now subtract 1 19/48 from 1

1 19/48 - 1 = 19/48

Finally, divide 19/48 by 320

320 x 48/19 = r808.42

To learn more about the division of fractions, please check: brainly.com/question/25779356

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Part 4. Find the missing sides for the 30 60 90 triangles. Please show work for each​
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l = tan(30) x 6√3

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11. tan(30) = c/30

c = 30 x tan(30)

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12.

sin(60) = 36/y

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3 years ago
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ming- LI spent $15 at the movies. She then earned $30 babysitting. She spent $12 at the bookstore. She ow has $18 left. How much
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Answer:

$29

Step-by-step explanation:

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A rectangle with an area of 103 square feet is dilated by a scale factor of 3. What is the new area?
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Simplify this equation <br> Thanks a lot!!!
den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

\bf\implies a^m \times b^m = (ab)^m

Using this property , we have ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

Simplifying using ( a+b)(a-b) = a² - b² ,

\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

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