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Nataly [62]
2 years ago
7

I use 1/12 of my salary to pay for rates and taxes,1/16 to pay for insurance and 5/6 to meet other expenses. if i have r320 left

of my monthly salary, calculate my yearly salary.​
Mathematics
1 answer:
omeli [17]2 years ago
6 0

The yearly salary after paying for taxes, insurances and other expenses is  r808.42.

<h3>What is the yearly salary?</h3>

The first step is to determine the total fraction used to pay for taxes, insurances and other expenses:

1/2 + 1/16 + 5/6

(48 + 6 + 80) / 96 = 134 / 96=  1 19/48

Now subtract 1 19/48 from 1

1 19/48 - 1 = 19/48

Finally, divide 19/48 by 320

320 x 48/19 = r808.42

To learn more about the division of fractions, please check: brainly.com/question/25779356

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tino4ka555 [31]

Answer:

x=7/2  x=7/3

Step-by-step explanation:

5 0
2 years ago
the number of televisions owned by Matt's classmates is 1, 4, 3, 3, 2, 1, and 7. what is the mean absolute deviation for the num
erik [133]
The answer is 3
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8 0
3 years ago
What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b
kramer

Option C: a=3, b=4 is the value of a and b

Explanation:

Given that the expression \sqrt{648}=\sqrt{2^a\times3^b}

We need to determine the value of a and b

Let us consider the term \sqrt{648} and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

648=2 \cdot 324

324 divides by 2,

648=2 \cdot 2 \cdot 162

162 divides by 2,

648=2 \cdot 2 \cdot 2 \cdot 81

81 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27

27 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9

9 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3

Thus, we have,

\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}

Therefore, equating the powers of 2 and 3, we get,

a=3, b=4

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0
3 years ago
Read 2 more answers
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
2 years ago
Solve the equation <br> |x-3| -10=-5
Deffense [45]

Answer:

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Step-by-step explanation:

|x-3| -10=-5

Add 10 to each side

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|x-3| =5

Now separate into two equations , one positive and one negative

x-3 = 5           x-3 = -5

Add 3 to each side

x-3+3 = 5+3    x-3+3 = -5 +3

x=8                     x=-2

5 0
2 years ago
Read 2 more answers
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