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3 years ago

9

VIN. ENRICHMENT ACTIVITY From the research topics that you enumerated in previous lesson, formulate your own title following the

given guidelines. 1. Research Title 1 2. Research Title 2 3. Research Title 3 4. Research Title 4 5. Research Title 5

1 answer:

sattari [20]3 years ago

8 0

HELPPPPPPPPPPPPPPPPPPPPPPP HELPPPPPPPPPPPPPPPPPPPPPPP and a few others i

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Two parallel plates that are initially uncharged are separated by 1.2 mm. What charge must be transferred from one plate to the

Gnoma [55]

Answer: 55.52 *10^-6 C= 55.52 μC

Explanation: In order to solve this question we have to take into account the following expressions:

potential energy stired in a capacitor is given by:

U=Q^2/(2*C) where Q and C are the charge and capacitance of the capacitor.

then we have:

Q^2= 2*C*U=

C=εo*A/d where A and d are the area and separation of the parallel plates capacitor

Q^2=2*εo*A*U/d=2*8.85*10^-12*1.9*10^-5*11*10^3/(1.2*10^-3)=

=55.52 *10^-6C

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3 years ago

The accepted standard measurement for mass is the A) liter. B) pound. C) Newton. D) kilogram.

andreev551 [17]

D) Kilograms is the standard unit of mass

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3 years ago

Graph are blank a relationship

Maru [420]

I have no clue sorry maybe try applying the answers and questions then I'll answer for u

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3 years ago

Light of wavelength 560 nm passes through a slit of width 0. 170 mm. (a) the width of the central maximum on a screen is 8. 00 m

faltersainse [42]

The distance between slit and the screen is 1.214m.

To find the answer, we have to know about the width of the central maximum.

<h3>How to find the distance between slit and the screen?</h3>

It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.

We have the expression for slit width w as,

$w=\frac{2*wavelength*d}{a}$

where, d is the distance between slit and the screen, and a is the slit width.

Thus, distance between slit and the screen is,

$d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m$

Thus, we can conclude that, the distance between slit and the screen is 1.214m.

Learn more about the width of the central maximum here:

brainly.com/question/13088191

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2 years ago

A stone is thrown horizontally at a speed of 10.0 m/s from the top of a cliff 139.4 m high.

Lesechka [4]

Answer:

a) 14.2sec

b) 1394m away if horizontal speed never changes

c) 9.8m/s

Explanation:

5 0

3 years ago