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anyanavicka [17]
3 years ago
5

A stone tumbles into a mine shaft and strikes bottom after falling for 4.2 second how deep is the mine shaft

Physics
1 answer:
rjkz [21]3 years ago
5 0
4.2*9.8\\41.16

41.16 meters
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A slender rod is 80.0 cm long and has mass 0.390 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05
Lilit [14]

Answer:

v = 1.08 m/s

Explanation:

What is the linear speed of the 0.0500-kg sphere as its passes through its lowest point?

The decrease in PE is

d = 80.0cm * 1 / 1000m = 0.80m

h = 0.80 m /2 = 0.40 m

ΔPE = m*g*h

ΔPE = (0.0500 - 0.0200)kg * 9.8m/s² * 0.400 m

ΔPE = 0.1176 J

The moment of inertia of the assembly is

I = 1/12*m*L² + (m1 + m2)*(L/2)²

I = 1/12*0.390kg*(0.800m)² + 0.0700kg*(0.400m)²

I = 0.032 kg·m²

KE = ½Iω²

0.1176 J = ½ * 0.032kg·m² * ω²

ω = 2.71 rad/s

v = ωr = 2.71 rad/s * 0.400m

The linear velocity

v = 1.08 m/s

3 0
3 years ago
The spheres are connected by a uncharged teflon rod. what is the charge on the left sphere after the charged plastic rod touches
vodomira [7]

The charge on the left sphere negatively charged.

<h3 /><h3>What is charge?</h3>

Due to the physical property of electric charge, charged material experiences a force when it is subjected to an electromagnetic field. You might be electrically positive or negative. While similar charges repel one another, opposite charges attract.

In order for the neutral metal sphere and negatively charged metal rod to have the same potential, some negative charge must flow from the rod to the sphere in order for them to both have negative charges.

The sum of the negative charges in them would be equal to the initial negative charge in the rod since the entire charge is preserved.

to learn more about charge go to -

brainly.com/question/18102056

#SPJ4

8 0
2 years ago
An astronaut circling the earth at an altitude of 400 km is horrified to discover that a cloud of space debris is moving in the
elena-14-01-66 [18.8K]

One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.

From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.

By equilibrium the centrifugal force and the gravitational force are equal therefore

F_c = F_g

\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}

Where

m = mass spacecraft

v = velocity

G = Gravitational Universal Constant

M = Mass of earth

r \rightarrow R+h \Rightarrow Radius of earth and orbit

Re-arrange to find the velocity

\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}

\frac{v^2_{orbit}}{r} = \frac{GM}{r^2}

v^2_{orbit}=\frac{GM}{r}

v_{orbit} = \sqrt{\frac{GM}{r}}

v_{orbit} = \sqrt{\frac{GM}{R+h}}

Replacing with our values we have

v_{orbit} = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{6.37*10^6+0.4*10^6}}

v_{orbit} = 7676m/s

From the cinematic equations of motion we have to

t = \frac{d}{2v_{orbit}} \rightarrow Remember that the speed is double for the counter-direction of the trajectories.

Replacing

t = \frac{29000m}{7676m/s}

t = 3.778s

Therefore the time required is 3.778s

4 0
3 years ago
Which is the transfer of thermal energy in matter with no overall transfer of matter? If you copy the answer from the last quest
kogti [31]

I believe radiation is the correct answer

8 0
3 years ago
Read 2 more answers
A car starts at a position of 2 km and moves to a final position of 4 km. what is the displacement of the car
Elza [17]
Should be just 2 km. - 2 km would mean it is moving in the opposite direction which come to think of it may be fine. You really can't tell.
8 0
3 years ago
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