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anyanavicka [17]
3 years ago
5

A stone tumbles into a mine shaft and strikes bottom after falling for 4.2 second how deep is the mine shaft

Physics
1 answer:
rjkz [21]3 years ago
5 0
4.2*9.8\\41.16

41.16 meters
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Answer:

18,375 kJ

Explanation:

Parameters given:

Density of water: 1000 kg/m³

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Dimensions of pool = 30m × 10m × 2.5m

Depth of pool = 2.5 m

First we need to find the mass of the water in the pool:

Density = mass/volume

Mass = density * volume

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Volume = 30 * 10 * 2.5 = 750 m³

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The work needed to be done is the product of the force required by the distance the water would need to move to be pumped out (depth of pool):

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3 years ago
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Technician A says a that a voltmeter can be used to monitor the output signal of an optical sensor. Technician B says that optic
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Answer:

B. Technician B only

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The net force on an object is equal to its mass times its acceleration.

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