All categories

3 years ago

How does Boyle's laws describe the relationship between gas pressure and volume?

Physics

1 answer:

Anon25 [30]3 years ago

5 0

Answer:

For a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. Or Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.

You might be interested in

A red ball is thrown down with an initial speed of 1.6 m/s from a height of 25 meters above the ground. Then, 0.4 seconds after

Radda [10]

Answer:

1. v = 22.2 m/s

2. t = 2.25 seconds

3. h = 27.05 m

4. t = 1.16 seconds

Explanation:

The questions involve motion under the influence of gravity

1. Using the formula v² = u² + 2gh

where u = 1.6 m/s; g= 9.81 m/s²; h = 25 m; v = ?

v² = (1.6)² + 2 * 9.81 * 25

√v² = √493.06

v = 22.2 m/s

2. Using h = ut + 1/2 gt²

where h = 25 m; u = 0 (since velocity on reaching the ground is zero); g = 9.81 m/s²; t = ?

therefore, h = 1/2 gt²

making t subject of the formula, t = √ (2*h /g)

t = √ (2 * 25 / 9.81)

t = 2.25 seconds

3. Time of travel for the blue ball, t = 2 - 0.4 = 1.6s

using h = ut - gt²

u = 24 m/s; t = 1.6 s; g = 9.81 m/s²

note: since the ball is travelling against gravity, g is negative

h = 24 * 1.6 - 11/2 * 9.81 * 1.6²

h = 38.4 - 12.55 = 25.85 m

since height above the ground is 1.2 m,

total height h = 25.85 m + 1.2 m

h = 27.05 m

4. Let the time of travel of the red ball be t seconds.

So the time of travel of the blue ball = (t - 0.4) seconds.

Both the balls are at the same height :

25 - s = 1.2 + h where s & h are the displacements of the red & the blue ball respectively.

25 - (ut + 1/2 gt2) = 1.2 + (ut - 1/2 gt2)

25 - (1.6 t + 0.5 * 9.8 t²) = 1.2 + (24(t-0.4) - 0.5*9.8*(t-0.4)²)

solving the equation above for the time after which both the balls are at the same height.

25 - 1.6t - 4.9t² = 1.2 + 24t - 9.6 - 4.9t² + 3.92t - 0.784

collecting like terms

(25 - 1.2 + 9.6 + 0.784) = (24 + 3.92 + 1.6) * t

t = 34.184 / 33.44

t = 1.16 seconds

6 0

3 years ago

The radius of the earth's very nearly circular orbit around the sun is 1.5 1011 m. find the magnitude of the earth's velocity, a

kotykmax [81]

The radius of Earth's circular trajectory is
$R=1.5*10^{11} m$
The time for the Earth to travel around the Sun is
$t=365(days)*24(hours)*3600(seconds) =3.1536*10^7 (s)$
Thus the velocity is velocity
$v=2\pi R/t =2\pi *1.5*10^{11}/(3.1536*10^{7})=2.99*10^4 (m/s)$
From this we can deduce the centripetal acceleration
$a=v^2/R =(2.99*10^4)^2/(1.5*10^{11}) =5.96*10^{-3} (m/s^2)$
Angular velocity is
$\omega =v/R =(2.99*10^4)/(1.5*10^{11})=2*10^{-7} (rad/s)$

5 0

4 years ago

Why is it important for scientist to do research?

sweet-ann [11.9K]

Answer:

Because if they dont research first they will be unprepared

Explanation:

3 0

3 years ago

Read 2 more answers

How does the image distance (di) of a convex lens compare with the image distance of a concave lens?

SVETLANKA909090 [29]

Correct Answer is A.

8 0

3 years ago

Read 2 more answers

If the thermal energy of the system increases by 400 J, and 1,100 J of heat were added to the system, how much work did the syst

Luba_88 [7]

700 J is the work done by the system.

<u>Explanation:</u>

The first law of thermodynamics is that the change in internal energy of the system is equal to the net heat transfer to the system minus the complete work performed by the system.

$\Delta \boldsymbol{U}=\boldsymbol{Q}-\boldsymbol{W}$

Where,

∆U – Change in internal energy

Q – Heat transfer to the system

Q – Work done

Here,

<u>Given data:</u>

∆U - 400 J

Q - 1100 J

We need to the work done by the system (W)

By applying the given values in the above equation, we get

400 = 1100 - W

W = 1100 - 400 = 700 J

7 0

3 years ago