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babymother [125]
3 years ago
14

Why is it necessary to check that n modifyingabove p with caret greater than or equals 5np≥5 and n modifyingabove q with caret g

reater than or equals 5nq≥5​?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0

Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if np \ge 5 and nq \ge 5 then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.

side note: q = 1-p is the complement of probability p

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The easiest way to solve this would be to convert 6 4/5 to a decimal. We know that to convert a fraction to a decimal, we must divide the numerator by the denominator. 

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So, 6 4/5 is 6.8 as a decimal. 

See how it's easier now that we've converted the mixed number to a decimal? 

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Answer:

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Step-by-step explanation:

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