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Snezhnost [94]
3 years ago
5

Why is the quotient of three divided by one-fifth different from the quotient of one-fifth divided by three?

Mathematics
1 answer:
aksik [14]3 years ago
7 0
We write the expressions first mathematically:
 three divided by one-fifth:
 (3) / (1/5)
 one-fifth divided by three:
 (1/5) / (3)
 We now use the double c method to find the results:
 (3) / (1/5) = (3 * 5) / (1 * 1) = 15/1 = 15
 (1/5) / (3) = (1 * 1) / (5 * 3) = 1/15 = 0.066666667
 The difference between the two is:
 15-0.066666667 = 14.93333333
 Answer 
 They are different because they are inverse expressions.
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In Professor Friedman's economics course the correlation betweenthe students' total scores before the final examination and thei
GalinKa [24]

Answer:

Q1

slope=0.16

intercept=30.2

Q2

78.2

Q3

36%

Step-by-step explanation:

Question 1

We are given that

xbar=280

sx=30

ybar=75

sy=8

r=0.6

The regression line can be written as

y=a+bx

a=intercept

b=slope

where

b=r\frac{sy}{sx}

and

a=ybar-bxbar

b=0.6*(8/30)

b=0.16

a=75-0.16*280

a=30.2

Thus,

slope=0.16

intercept=30.2

Question 2

The regression line in the given scenario

y=30.2+0.16x

Julie pre exam total before the exam was 300.

y=30.2+0.16*300

y=30.2+48=78.2

So, the predicted final exam score of Julie is 78.2.

Question 3

R² denotes the variation in dependent variable y explained by the linear relationship of x and y.

R²=0.6²=0.36

Thus, the proportion of the variation in final exam scores that is explained by the linear relationship between pre-exam scores and final exam scores is 36%.

5 0
4 years ago
Can someone put this in slope intercept form <br> 2x-3y=12
Stells [14]

Answer:

Step-by-step explanation:

2x-3y=12

y=2/3x-4

7 0
3 years ago
The Bears have won 7 and tied 2 of their last 13 games. They have not forfeited any games. Which ratio correctly compares their
nataly862011 [7]

Answer:

7:4

Step-by-step explanation:

7:4 because if 13 is the total amount of games, that minus the amount of games won and tied equals the amount of games loss which is 4. Since it says wins to losses, the wins will come first in the ratio. Therefore the correct answer would be 7:4.

8 0
3 years ago
If points A and B are randomly placed on the circumference of a circle with a radius of 2 cm, what is the probability that the l
OLga [1]

Answer:

The probability that the length of chord AB > 2 cm is 2/3 ⇒ D

Step-by-step explanation:

* Lets explain how to solve the problem

- Points A and B are randomly placed on the circumference of a

 circle with a radius of 2 cm

- We need to find the probability that the length of chord AB is

 greater than 2 cm

<em>- </em>Probability = required length of arc / circumference

- <em>Assume that the length of the chord AB is 2 and the center of </em>

<em>  the circle is labeled M</em>

- The radius of the circle is 2 and AB = 2

- In Δ AMB

∵ MA= MB = 2 radii

∵ AB = 2

∴ Δ AMB is an equilateral triangle

∴ m∠AMB = π/3

∵ The length of an arc = r Ф , where r is the radius of the circle and

  Ф is the central angle subtended by this arc

∵ r = 2 , Ф = π/3

∴ The length of arc AB = 2 × π/3 = 2π/3

- The arc AB is in the half of the circle then there are another arc

  with the same length in the other half of the circle

- The length of the arc we must excluded from the length of the

  circle to have the part of length of AB is greater than 2 is

   2(2π/3) = 4π/3

∴ The length of the excluded arc is 4π/3

∵ The length of the circle is 2πr

∵ r = 2

∴ The length of the circle = 2π(2) = 4π

- <em>The required arc = length circle - length excluded arc</em>

∵ The length of the excluded arc = 4π/3

∵ The length of the circle = 4π

∴ The required arc = 4π - 4π/3 = 8π/3

- <em>Probability = required length of arc / circumference</em>

∴ Probability = (8π/3)/(4π) = 2/3

∴ The probability that the length of chord AB > 2 cm is 2/3

4 0
3 years ago
Toby has made 298 goals out of 347 goals attempted.
IceJOKER [234]

Answer:

Convert fraction (ratio) 298 / 347 Answer: 85.878962536023%

Step-by-step explanation:

5 0
3 years ago
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