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3 years ago

Solve for m angle BCD if m angle BCE=42^ and m angle ECD=41^

Mathematics

2 answers:

maksim [4K]3 years ago

5 0

Step-by-step explanation:

total angle, < BCD = 42°+41° = 83°.

Hope this helps you.

Alex Ar [27]3 years ago

5 0

Answer:

BCD = 83

Step-by-step explanation:

We can use the angle sum addition

BCD = BCE + ECD

BCD = 42+41

BCD = 83

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3 years ago

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Step-by-step explanation:

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PLS HELP ! Will give brainliest!

Rasek [7]

Given:

The quadratic equation is :

$16x^2-20x-6=0$

To find:

The quadratic formula for the given equation after substituting the values.

Solution:

If a quadratic equation is $ax^2+bx+c=0$ , then the quadratic formula is:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$16x^2-20x-6=0$

In this equation, $a=16,b=-20,c=-6$ .

Substituting $a=16,b=-20,c=-6$ in the above formula, we get

$x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}$

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