I believe the answer is A.
hope I helped
Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
-1.6
Step-by-step explanation:
4x-2/5
=-8/5
=-1.6
Tables are easy to make when u have the equation. Just simply sub any number in for x and solve for y
y = 3x + 2...lets let x = 0
y = 3(0) + 2
y = 2.....so when x = 0, y = 2....(0,2)
y = 3x + 2....lets let x = 1
y = 3(1) + 2
y = 3 + 2
y = 5....so when x = 1, y = 5....(1,5)
y = 3x + 2.....let x = 2
y = 3(2) + 2
y = 6 + 2
y = 8....so when x = 2, y = 8...(2,8)
u can find more point if u need to...
now make a table..
x y
0 2
1 5
2 8
and like I said, if u need more numbers for ur table, just do like I did above :)
