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Andrew [12]
3 years ago
10

*50 points*

Mathematics
2 answers:
Vesna [10]3 years ago
7 0
I agree with The person that answered before me
xxMikexx [17]3 years ago
6 0

Answer:

6

Step-by-step explanation:

root the 216 as it is a cube

:edge *edge *edge =volume

Since all edges are the same, just root it

I hope this helped  if it did please mark me Brainliest

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PLZ answer ASAP!!!!! Due at midnight!!
Lapatulllka [165]
Answer: D

Good luck !
3 0
2 years ago
Read 2 more answers
The mean of five numbers is 8. If one of the five numbers is removed, the mean becomes 9. What is the value of the number that w
mestny [16]

Using the mean concept, it is found that the value of the number that was removed was of 4.

<h3>What is the mean?</h3>

The mean of a data-set is given by the <u>sum of all observations in the data-set divided by the number of observations</u>.

The mean of five numbers is 8, hence, the sum of the numbers is given by:

S = 5 x 8 = 40.

If one of the five numbers is removed, the mean becomes 9, hence, the sum of the four numbers is given by:

S = 4 x 9 = 36.

The difference is:

40 - 36 = 4.

Hence, the value of the number that was removed was of 4.

More can be learned about the mean concept at brainly.com/question/25122507

#SPJ1

3 0
2 years ago
What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def
Misha Larkins [42]
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1

If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)

If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)

however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1

If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1

and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)

Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
8 0
3 years ago
Which polynomial equation of least degree has -2, -2, 3, and 3 as four of its roots? (x + 2)(x - 3) = 0 (x - 2)-2(x + 3)3 = 0 (x
azamat

Answer:

(x + 2)²(x - 3)² = 0

Step-by-step explanation:

Since we have a degree of 2 and double of the same roots, we know that each root would have a multiplicity of 2. Therefore, our answer is(x + 2)²(x - 3)² = 0

6 0
3 years ago
Please help and thanks in advance <br><br><br> Add 0.65 and 0.24. How many tenths are in the sum?
elena-s [515]
There are 8 tenths in the sum. .65+.24 is .89. tenths are the first digit to the right of the decimal. 80 and 8x10=80
6 0
3 years ago
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