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meriva
3 years ago
15

Each diagram is made of smaller, identical pieces. Tell how many pieces you would shade to model 25%

Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

12 pieces

Step-by-step explanation:

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Divide 2/7 by 1/3 please help me
nlexa [21]

Answer:

6/7

Step-by-step explanation:

i am not sure if your question cut off but i am going to answer what i see on my side of the screen.

2/7 divided by 1/3 is the same as 2/7 times 3/1; since we multiply by the reciprocal when we divide fractions.

Therefore,

2/7 * 3/1 = 6/7

7 0
2 years ago
What is a histogram? i have a question on it and i dont know how to answer it
o-na [289]
It is <span>a </span>statistical graph<span> that represents the </span>frequency<span> of values of a quantity by </span>verticalrectangles<span> of </span>varying<span> heights and </span>widths<span>. The width of the rectangles is in </span>proportion<span> to the class </span>interval<span> under </span>consideration<span>, and their areas represent the relative frequency of the </span>phenomenon<span> in </span><span>question. And this is one of example of histogram:</span>

5 0
3 years ago
6, 8, 11, 12, 2x – 8, 2x + 10, 35, 41, 42, 50
krok68 [10]

Answer:

12

Step-by-step explanation:

(2x-8+2x+10)/2 = 25

(4x+2) = 2×25

4x+2 = 50

4x = 50-2

4x = 48

x = 48/4

x = 12

6 0
3 years ago
Read 2 more answers
Help! I need help with finding the value of x.
Dmitry_Shevchenko [17]

Answer:

x = 18.64

Step-by-step explanation:

use tan:

⇒ tan = \frac{opposite}{adjacent}

⇒ tan 46 = \frac{18}{x}

tan of 46 is 1.0355

⇒ 1.0356 = \frac{18}{x}

multiply 18 on both sides

⇒ 1.0355 x 18 = \frac{18}{x} x 18

⇒ 18.64 = x

6 0
3 years ago
Evaluate the given integral by making an appropriate change of variables, where r is the rectangle enclosed by the lines x - y =
vova2212 [387]
\begin{cases}u=x-y\\v=x+y\end{cases}

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial u}{\partial y}\\\\\dfrac{\partial v}{\partial x}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&-1\\1&1\end{bmatrix}
\implies\det\mathbf J=2

The area of the region is then given by

\displaystyle\iint_R\mathrm dA=\int_{u=0}^{u=7}\int_{v=0}^{v=6}2\,\mathrm dv\,\mathrm du=84
6 0
3 years ago
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