E^(∞): This is defined as 'e' being raised to a huge value. Hence the result will definitely be a large number which is also infinity (∞), i.e. e^(∞) = ∞.
e^(- ∞) = 1/e^(∞) = 1/∞ = 0.
        
             
        
        
        
Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0  
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25 
Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)
 P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3) 
P(X=3)=p(3,1) +p(3,2) +p(3,3) 
P(X=3)=0.05+0.1+0.25=0.4

Hence P(Y=1|X=3)=0.125
 
        
             
        
        
        
I’m not quite sure what the question is, but 81 cookies distributed among 44 people would mean that each person gets 0.02 cookies each.
        
                    
             
        
        
        
The factor is x-6 since the two factors of your equation are (6x-6) and (x-6)
        
                    
             
        
        
        
Answer: I'm pretty sure the correct answer is C.