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3 years ago

5

5. The force per unit charge is known as

1 answer:

mestny [16]3 years ago

7 0

Answer:

b

Explanation:

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Matt is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his spe

Olin [163]

(150 meters) / (18 seconds) = 8.33 meters per second

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3 years ago

A curved, transparent object used to refract light

zlopas [31]

It's called a concave lens.

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3 years ago

Imagine a car moving down a street. From which reference point would the

antiseptic1488 [7]

Answer:

From the car

Explanation:

You are in motion

Hope this helps

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3 years ago

Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9×1022k

Taya2010 [7]

Answer: $g=1.97 m/s^2$

Explanation:

Given

mass of Jupiter is $M=4.9\times 10^{22} kg$

Density of Jupiter is same as Earth

$density\ of\ Earth=density\ of\ Jupiter=5510 kg/m^3$

$mass=volume\times density$

considering Jupiter to be sphere of radius r

$M=\frac{4}{3}\times \pi r^3\times \rho$

$r^3=\frac{3M}{\rho \times 4\pi}$

$r^3=\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi}$

$r=(\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi})^{\frac{1}{3}}$

$r=1.28\times 10^6 m$

acceleration due to gravity is given by

$g=\frac{GM}{r^2}$

$g=\frac{6.67\times 10^{-11}\times 4.9\times 10^{22}}{(1.28\times 10^6)^2}$

$g=1.97 m/s^2$

3 0

4 years ago

Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,00

wlad13 [49]

Answer:

Power output = $2\times 10^4\ W$

Explanation:

Given:

Mass of the elevator is, $m=1000\ kg$

Height to which it is raised is, $h=10\ m$

Acceleration due to gravity is, $g=10\ m/s^2(Approximately)$

Time taken by the motor to raise the elevator is, $t=5.0\ s$

Now, work done on the elevator by the motor is equal to the increase in the gravitational potential energy of the elevator.

Increase in gravitational potential energy is given as:

$\Delta U=mgh=(1000)(10)(10)=10\times 10^4\ J$

Therefore, work done by motor is, $W=10\times 10^4\ J$

Now, we know that, power is work done in unit time. So, power output is given as:

$Power=\frac{W}{t}\\\\Power=\frac{10\times 10^4\ J}{5.0\ s}\\\\Power=2\times 10^4\ J/s\\\\Power=2\times 10^4\ W..........[1 W = 1\ J/s]$

Therefore, the power output of the first motor is $2\times 10^4\ W$

7 0

4 years ago