Answer:
The speed and direction of each ball after the collision is 1.27 m/s to East direction and 5.07 m/s to East direction.
Explanation:
given information
m₁ = 0.440 kg
v₁ = 3.80 m/s
m₂ = 0.220 kg
v₂ = 0
collision is perfectly elastic
v₁ - v₂ = - (v₁'- v₂')
v₁ = - (v₁'- v₂')
v₂' = v₁ + v₁'
according to momentum conservation energy
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁v₁ = m₁v₁' + m₂(v₁ + v₁')
m₁v₁ = m₁v₁' + m₂v₁ + m₂v₁'
m₁v₁ - m₂v₁ = m₁v₁' + m₂v₁'
v₁ (m₁ - m₂) = (m₁ + m₂) v₁'
v₁' = (m₁ - m₂)v₁ / (m₁ + m₂)
= (0.440 - 0.220) (3.8) / (0.440 + 0.220)
= 1.27 m/s to East direction
v₂' = v₁ + v₁'
= 3.8 + 1.27
= 5.07 m/s to East direction
'Displacement' is the distance and direction between the starting point and
ending point, regardless of the path followed to get there.
A particle that's executing simple harmonic motion is always in the same place
where it was one time period ago, and where it will be later after another time
period has passed.
So its displacement during exactly one time period is exactly zero.
The answer would be B.
Since the light source comes from the bottom, you just need to find the sequence from the bottom going up.
It will start with the light source, then go through the slide, which will then go through the objective lens and lastly, the eyepiece lens. In summary, the sequence is:
B. Light --- slide ---- objective lens --- eyepiece lens
Voltage is necessary for charge to flow
<h2>
Answer: A</h2>
Explanation because the distance covered is equal time intervals is the same or equal.
